All categories

2 years ago

Are all perfect cubes also multiples of three? Are all multiples of three also perfect cubes?

Mathematics

2 answers:

Phoenix [80]2 years ago

6 0

Answer:

h free wnxnsjjsndjejdkwlsjfnekskdjfjekakxjfjqia

DanielleElmas [232]2 years ago

4 0

Jkjhccgg knife jcii

You might be interested in

if two angles in one triangle are congruent to two angles in another triangle, then the third pair of angles must also congruent

SVEN [57.7K]

Answer:

i believe the answer is true

Step-by-step explanation:

6 0

2 years ago

A 25-foot ladder is placed against a vertical wall. Suppose the bottom of the ladder slides away from the wall at a constant ra

dsp73

Answer: The ladder is sliding down the wall at a rate of $5\dfrac{17}{50}\ ft/sec$

Step-by-step explanation:

Since we have given that

Length of ladder = 25 foot

Distance from the wall to the bottom of ladder = 15 feet

Let base be 'x'.

Let length of wall be 'y'.

So, by pythagorus theorem, we get that

$x^2+y^2=25^2\\\\15^2+y^2+625\\\\225+y^2=625\\\\y^2=625-225\\\\y^2=400\\\\y=\sqrt{400}\\\\y=20\ feet$

$\dfrac{dy}{dx}=-4\ ft/sec$

Now, the equation would be

$x^2+y^2=625\\$

Differentiating w.r.t x, we get that

$2x\dfrac{dx}{dt}+2y.\dfrac{dy}{dt}=0\\\\2\times 15\dfrac{dx}{dt}+2\times 20\times -4=0\\\\30\dfrac{dx}{dt}-160=0\\\\\dfrac{dx}{dt}=\dfrac{160}{30}=5.34\ ft/sec$

Hence, the ladder is sliding down the wall at a rate of $5\dfrac{17}{50}\ ft/sec$

8 0

3 years ago

Write the equation of a line passing (5,6) and (4,3) in slope-intersept

topjm [15]

Step-by-step explanation:

$gradient = \frac{(3 - 6)}{(4 - 5)} \\ = 3 \\ y = mx + c \\ consinder \: (4, \: 3) \\ 3 = (3 \times 4) + c \\ c = - 9 \\ y = mx + c \\ y = 3x - 9$

5 0

2 years ago

Read 2 more answers

The following question involves a standard deck of 52 playing cards. In such a deck of cards there are four suits of 13 cards ea

olasank [31]

Answer:

(a)No. The probability of drawing a specific second card depends on the identity of the first card.

(b)4/663

(d) 8/663

Step-by-step explanation:

(a)The events are not independent because we are drawing cards without replacement and the probability of drawing a specific second card depends on the identity of the first card.

(b) P(ace on 1st card and jack on 2nd).

$P$(Ace on 1st card) =\dfrac{4}{52}\\ P$(Jack on 2nd card)=\dfrac{4}{51}\\\\$Therefore:\\P(ace on 1st card and jack on 2nd) =\dfrac{4}{52}\times \dfrac{4}{51}\\=\dfrac{4}{663}$

(c)P(jack on 1st card and ace on 2nd)

$P$(Jack on 1st card) =\dfrac{4}{52}\\ P$(Ace on 2nd card)=\dfrac{4}{51}\\\\$Therefore:\\P(jack on 1st card and ace on 2nd) =\dfrac{4}{52}\times \dfrac{4}{51}\\=\dfrac{4}{663}$

(d)Probability of drawing an ace and a jack in either order.

We can either draw an ace first, jack second or jack first, ace second.

Therefore:

P(drawing an ace and a jack in either order) =P(AJ)+(JA)

From parts (b) and (c) above:

$P$(jack on 1st card and ace on 2nd) =\dfrac{4}{663}\\P$(ace on 1st card and jack on 2nd) =\dfrac{4}{663}\\$Therefore:\\P(drawing an ace and a jack in either order)=\dfrac{4}{663}+\dfrac{4}{663}\\=\dfrac{8}{663}$

6 0

3 years ago

Calculate the area of this trapezium.<br> 6 cm<br> 4 cm<br> 5 cm<br> 8 cm

irga5000 [103]

area=1/2(AB+0A)Ac=4cm

8 0

2 years ago

Read 2 more answers