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Zolol [24]
3 years ago
13

Are all perfect cubes also multiples of three? Are all multiples of three also perfect cubes?

Mathematics
2 answers:
Phoenix [80]3 years ago
6 0

Answer:

h free wnxnsjjsndjejdkwlsjfnekskdjfjekakxjfjqia

DanielleElmas [232]3 years ago
4 0
Jkjhccgg knife jcii
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Stacy uses 6 cups of sugar to make 120 brownies how many cups of sugar will she use to make 360 brownies?
oksian1 [2.3K]

Answer:

18 cups of sugar

Step-by-step explanation:

Step 1:

120 ÷  6 = 20

Step 2:

360 ÷ 20

Answer:

18

Hope This Helps :)

8 0
3 years ago
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The weights of NCAA lacrosse players are approximately normally distributed with a mean of 182 lbs and a standard deviation of 1
Marizza181 [45]

Answer:

What can I do for you

Step-by-step explanation:

4 0
3 years ago
Which image shows a reflection of the figure below?
uysha [10]
The answer is the third image.

It shows the original image reflected across the y-axis.

Hope this helps! :)
8 0
3 years ago
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During the past 10 years, the amount of money, M (in billions of dollars), spent in North America by car dealerships advertising
rewona [7]

Answer: I believe the 23rd, but if its in 10 years I must be wrong

I graphed the equation, but replaced t with x




6 0
3 years ago
Suppose a tub has the shape of an elliptical paraboloid given by z = ax2+by2 (where a, b are some positive constants). If a marb
Umnica [9.8K]

Answer:

It would roll in this direction.

\nu  =  (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})

Step-by-step explanation:

It would roll to the direction of maximum decrease, which is the -1 times the direction of maximum increase, which is given by the gradient of the function.  

Since  

z =  ax^2  + by^2

For this case, the gradient of your function would be

\nabla z  = (2ax , 2by)

And  -1  times the gradient of your function would be

-\nabla z  = (-2ax , -2by)\\

Then, at

 (1,1,a+b),\\x = 1 \\y = 1

So it would go towards

v = (-2a,-2b)

The magnitud of that vector is

|v| =  2\sqrt{a^2+b^2}

and to conclude it would roll in this direction.

\nu  =  (-a/\sqrt{a^2+b^2},-b/\sqrt{a^2+b^2})

6 0
3 years ago
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