Pythagoras Theorem:
hipotenuse²=leg₁²+leg₂²
First posible triangle:
hypotenuse=13 (13²=169)
leg₁=12 ( 12²=144)
leg₂=5 (5²=25)
13³=144 + 25
Answer:can be side lengths of a triangle
Second triangle:
hypotenuse=12.6 (12.6²=158.76)
leg₁=6.7 ( 6.7²=44.89)
leg₂=6.5 (6.5²=42.25)
leg₁²+leg₂²=44.89+42.25=87.14≠158.76
Answer: cannot be side lenghts of a triangle.
third triangle:
hypotenuse=13 (13²=169)
leg₁=12 ( 12²=144)
leg₂=11 (11²=121)
leg₁²+leg₂²=144+121=265≠169
Answer: cannot be side lenghts of a triangle.
fourth triangle:
hypotenuse=13 (13²=169)
leg₁=6 ( 6²=36)
leg₂=4 (4²=16)
leg₁²+leg₁²=36+16=52≠169
Answer: cannot be side lenghts of a triangle.
Answer:
$85
Step-by-step explanation:
<u>Earning:</u>
<u>Spending:</u>
- $25 + $10 + $25 + $35 = $95
<u>Amount available for saving:</u>
Answer: 28 red marbles
Step-by-step explanation:
Since there are in total 140 marbles and there are 5 red marbles, just simply divide 140 by 5 and you get your answer. 28 red marbles.
Hello can you help me Solve each system of equations by GRAPHING. Clearly identify your solution.
(4x-y=3)
(3x+y=4)
Please help I need this answer and an explanation of how you got it I really do need this if you can help please it would mean so much to me I REALLY NEED HELPPPP
