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Sindrei [870]
2 years ago
11

This probability distribution shows the typical grade distribution for a Geometry course with 35 students. Find the probability

that a student earns a grade of A, B, or C. Enter a decimal rounded to the nearest hundredth.

Mathematics
2 answers:
iris [78.8K]2 years ago
5 0

Answer:

.86

Step-by-step explanation:

There are 5+10+15 = 30 students that earned and A, B or C

P( A, B or C) = number of students that earned and A ,B , C / total

                    =30/35

                    =.857142857

   Rounded to the nearest hundredth

                   =.86

iris [78.8K]2 years ago
5 0
  • Total marks=5+10+15+3+2=36
  • No of students earned A,B,C=5+10+15=30

\\ \rm\Rrightarrow P(A,B,C)

\\ \rm\Rrightarrow \dfrac{30}{36}

\\ \rm\Rrightarrow 0.85

\\ \rm\Rrightarrow 0.86

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3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Cboxed%7B%20%5Cbegin%7Barray%7D%7B%7D%5Clarge%5Ctt%20The%20%20%5C%5C%20%20%5Ct
larisa86 [58]

Distance formula

\boxed{\sf \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}

Now

#1

\\ \tt\Rrightarrow AB=\sqrt{(3-3)^2+(-2-8)^2}=\sqrt{100}=10units

#2

\\ \tt\Rrightarrow OK=\sqrt{(5-7)^2+(-2+2)^2}=\sqrt{4}=2units

#3

\\ \tt\Rrightarrow LM=\sqrt{(-4-4)^2+(6+4)^2}=\sqrt{64+100}=\sqrt{164}\approx 13units

#4

\\ \tt\Rrightarrow PC=\sqrt{(5-2)^2+(1-3)^2}=\sqrt{9+4}=\sqrt{13}=3.2units

#5

\\ \tt\Rrightarrow QR=\sqrt{(-2+10)^2+(3-9)^2}=\sqrt{64+36}=\sqrt{100}=10units

8 0
2 years ago
Read 2 more answers
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