Solution: We are given:

Let
be the weight (oz) of laptop
We have to find 
To find the this probability, we need to find the z score value.
The z score is given below:



Now, we have to find 
Using the standard normal table, we have:

0.9236 or 92.36% of laptops are overweight
Note that

in the given closed interval, so the area is exactly given by the definite integral

(no absolute values needed!)
Integrating gives
Answer:
They are equal
Step-by-step explanation:
320 oz is 20 pounds:))
Answer:
(-2, 4)
Step-by-step explanation:
Hopes this helps!