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Helen [10]
3 years ago
12

Someone help solve it please

Mathematics
1 answer:
lara31 [8.8K]3 years ago
6 0

Answer: 10

Step-by-step explanation:

The x-intercepts means when y equals 0, or when the function crosses the x-axis.

0 = (x-6)^2 - 16

16 = (x-6)^2

Take the square root of both sides:

4 = (x-6)

Add 6 to both sides to get:

x = 10

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Find the value of 4+n when n=12
Semmy [17]

Answer:

16

Step-by-step explanation:

N equals 12, so

4 + 12 = 16

5 0
3 years ago
Read 2 more answers
A simple random sample from a population with a normal distribution of 98 body temperatures has x =98.90 °F and s =0.68°F. Const
Ludmilka [50]

Answer:

0.609 \leq \sigma \leq 0.772  

And the best conclusion would be:

D. This conclusion is safe because 1.40 °F is outside the confidence interval.

Step-by-step explanation:

1) Data given and notation  

s=0.68 represent the sample standard deviation  

\bar x =98.90 represent the sample mean  

n=98 the sample size  

Confidence=90% or 0.90  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .  

2) Calculating the confidence interval  

The confidence interval for the population variance is given by the following formula:  

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}  

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:  

df=n-1=98-1=97  

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,97)" "=CHISQ.INV(0.95,97)". so for this case the critical values are:  

\chi^2_{\alpha/2}=120.990  

\chi^2_{1- \alpha/2}=75.282  

And replacing into the formula for the interval we got:  

\frac{(97)(0.68)^2}{120.990} \leq \sigma \leq \frac{(97)(0.68)^2}{75.282}  

0.371 \leq \sigma^2 \leq 0.596  

Now we just take square root on both sides of the interval and we got:  

0.609 \leq \sigma \leq 0.772  

And the best conclusion would be:

D. This conclusion is safe because 1.40 °F is outside the confidence interval.

3 0
4 years ago
What is the solution to the system of equations above?
sergejj [24]

Answer:

(-2,-2)

Step-by-step explanation:

the x is -2

also the y is -2

8 0
3 years ago
Wyatt went on a 40 mile bike ride. If his average speed was 7 1/2 miles per hour, how long did his trip take?
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You would do 40 divided by 7.5
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3 years ago
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Can someone please help me ;-; this is due today
Assoli18 [71]

Answer:

it looks like E (correction)

Step-by-step explanation:

this site may help you.

https://www.mathwarehouse.com/geometry/triangles/triangle-types.php

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