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3 years ago

13

At a college, approximately 2 out of 5 seniors go on to attend graduate school. if there are 750 seniors at the college, how man

y would be expected to

1 answer:

Tresset [83]3 years ago

5 0

40/100=x/750 cross multiply

You might be interested in

2/11 into lowest terms

docker41 [41]

If you mean lowest terms as in fully simplified, then your fraction "2/11" is already in lowest terms.
Lowest terms mean that your numerator and denominator have no common factors apart from 1.

2 and 11 don't have any common factors, therefore 2/11 is in lowest terms already.

5 0

2 years ago

Solve the equation 5y-6=10

BaLLatris [955]

Answer:

y = 3.2

Step-by-step explanation:

Simplifying

5y + -6 = 10

Reorder the terms:

-6 + 5y = 10

Solving

-6 + 5y = 10

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '6' to each side of the equation.

-6 + 6 + 5y = 10 + 6

Combine like terms: -6 + 6 = 0

0 + 5y = 10 + 6

5y = 10 + 6

Combine like terms: 10 + 6 = 16

5y = 16

Divide each side by '5'.

y = 3.2

Simplifying

y = 3.2

8 0

2 years ago

Read 2 more answers

Solve for b.<br> 7<br> b<br> 12<br> b= ✓ [?]<br> Pythagorean Theorem: a2 + b2 = c2<br> Enter

fomenos

Answer: $b=\sqrt{95}$

Step-by-step explanation:

To solve for b, we want to use the Pythagorean Theorem as given.

b and 7 are the legs, and 12 is the hypotenuse.

$7^2+b^2=12^2$ [exponent]

$49+b^2=144$ [subtract both sides by 49]

$b^2=95$ [square root both sides]

$b=\sqrt{95}$

Now we know $b=\sqrt{95}$ .

6 0

2 years ago

Make r the subject of the formula <br>v = \pi \: h {}^{2}(r - \frac{h}{3})v=πh2(r−3h) <br>

mel-nik [20]

Answer:

$\boxed{r = \frac{h}{3} + \frac{v}{\pi {h}^{2} } }$

Step-by-step explanation:

$Solve \: for \: r: \\ = > v= \pi {h}^{2}(r - \frac{h}{3} ) \\ \\ v=\pi {h}^{2}(r - \frac{h}{3} )is \: equivalent \: to \: {h}^{2}\pi(r - \frac{h}{3} ) = v: \\ = > {h}^{2}\pi(r - \frac{h}{3} ) = v \\ \\ Divide \: both \: sides \: by \: \pi {h}^{2} : \\ = > r - \frac{h}{3} = \frac{v}{\pi {h}^{2} } \\ \\ Add \: \frac{h}{3} \: to \: both \: sides: \\ = > r = \frac{h}{3} + \frac{v}{\pi {h}^{2} }$

7 0

2 years ago

Suppose that the value of a stock varies each day from $13 to $24 with a uniform distribution. (a) Find the probability that the

bogdanovich [222]

Answer:

a. P= 0.6364

b. P = 0.3636

c. Q = $21.25

d. P = 0.5

Step-by-step explanation:

given data

value of a stock varies = $13 to $24

solution

P (stock value is more than $17)

P = $\frac{(24-17)}{(24-13)}$

P = $\frac{7}{11}$

P = 0.6364

and

P (value of the stock is between $17 and $21)

P = $\frac{(21-17)}{(24-13)}$

P = $\frac{4}{11}$

P = 0.3636

and

Let the upper quartile be Q

$\frac{(24 - Q)}{(24 - 13)} = 0.25$

$\frac{(24 - Q)}{11} = 0.25$

(24 - Q) = 2.75

so

Q = $21.25

and

P(X > 20 | X > 16)

P = $\frac{(24-20)}{(24-16)}$

P = $\frac{4}{8}$

P = 0.5

3 0

3 years ago