Answer:
decreasing
Step-by-step explanation:
"Increasing" means the graph is going up from left to right.
"Decreasing" means the graph is going down from left to right.
"Constant" means the graph is "flat" (this is not a technical term) it is keeping the same y value, neither going up nor going down.
What can be super confusing is the
(2.2, 5) mentioned in the question. THIS IS NOT A POINT. It is an interval and points and intervals unfortunately have the same notation sometimes.
An "interval" is a section of the graph, here: FROM 2.2 not including 2.2, TO 5 not including 5. These are like the address on the x-axis. If you look at your graph at 2.2 on the x-axis, it is a peak(relative maximum) and it goes down to the right to where x is 5 where it bottoms out (relative minimum) So on that interval, from 2.2 to 5, the graph is DECREASING.
Answer:
b. interest rate per period
Step-by-step explanation:
We know that
Annual interest rate is APR or (r)
Po is initial amount
n is number of periods
t is time in years
A is the amount after t years
so,
i is the interest rate per period
Hence ,
answer is
i is the interest rate per period
Answer;
7.77
Step-by-step explanation:
Answer:
<h2>The area of the triangular base = 8 ft²</h2>
Step-by-step explanation:
The formula of a volume of a prism:


We have

Substitute:
<em>divide both sides by 9</em>

Question:
Yuet solved the equation
for a.
Her steps are shown below.
1. Subtract 2b: 
2. Divide by 6: 
Answer:
In step 1 she needed to add 2b to both sides of the equation.
Step-by-step explanation:
Given:
The above steps shows how Yuet solved an equation
Required:
True statement about Yuet's work
The implication of the statement is to state what Yuet should have done instead of what she did.
In step 1, she subtracted 2b from both sides of the equation; this is wrong.
Instead of subtracting, she ought to add 2b to both sides of the equation.
The correct steps and result is as follows:
1. Add 2b: 
2. Divide by 6: 
Hence, we can conclude that in step 1 she needed to add 2b to both sides of the equation.