Question

What is the volume of a cone with a height of 9.5 inches and a radius of 8 inches? Cone V = 1 3 Bh 1. Rewrite the formula for the base area: V = 1 3 πr2h
2. Substitute the values into the formula: V = 1 3 π(82)(9.5)
3.Evaluate the power:V = 1 3 π(64)(9.5)
4.Simplify using multiplication: V = 1 3 π(608)
The cone has a volume of?

Answer 1

Answer:

$202.666\pi inches^3$

Step-by-step explanation:

Given :

Height of cone = 9.5 inches

Radius of cone = 8 inches

To Find: Volume of cone

Solution:

Volume of cone = $\frac{1}{3}\pi r^2 h$

                           = $\frac{1}{3}\pi (8)^2 (9.5)$

                           = $\pi 202.666$

Thus the volume of the given cone is $202.666\pi inches^3$

Answer 2

Answer:

636.4 in³  

Step-by-step explanation:

Volume of a cone is given by:

$V = \frac{1}{3}\pi r^2 h$

where r is the radius of the base of the cone and h is its height.

It is given that, the radius of the base of the cone is, r = 8 in

The height of the cone is, h = 9.5

$\Rightarrow V = \frac{1}{3} \times 3.14 \times (8)^2 (9.5) = 636.4 in^3$

Thus, the volume of the cone is 636.4 in³