20 divided by 4 - 5+12

2 answers:

7 0

The answer is 12. you first divide 20 by 4 and get 5. then you subtract 5 by 5 and get 0. then you add 12 plus 0 and get 12

Hope I Helped :D

lana66690 [7]3 years ago

4 0

Answer:

The answer is 12

Step-by-step explanation:

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This problem is taken from the delightful book "Problems for Mathematicians, Young and Old" by Paul R. Halmos. Suppose that 681

aleksley [76]

Answer:

680 games

Step-by-step explanation:

Suppose that 681 tennis players want to play an elimination tournament.

1st round:

One of 681 players, chosen at random, sits out that round and 680 players play. There will be 340 winners plus one player which sits - 341 players for the next round and 340 games

2nd round:

There will be 170 winners plus one player which sits - 171 players for the next round and 170 games

3rd round:

There will be 85 winners plus one player which sits - 86 players for the next round and 85 games

4th round:

There will be 43 winners - 43 players for the next round and 43 games

5th round:

There will be 21 winners plus one player which sits - 22 players for the next round and 21 games

6th round:

There will be 11 winners - 11 players for the next round and 11 games

7th round:

There will be 5 winners plus one player which sits - 6 players for the next round and 5 games

8th round:

There will be 3 winners - 3 players for the next round and 3 games

9th round:

There will be 1 winner plus one player which sits - 2 players for the next round and 1 game

10th round - final:

1 champion and 1 game.

In total,

340 + 170 + 85 + 43 + 21 + 11 + 5 + 3 + 1 + 1 = 680 games

4 0

3 years ago

Make c the subject:<br> x=-b+(b²-4ac) divided by 2a<br><br> The brackets mean square root

kipiarov [429]

$x=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\
2ax=-b+\sqrt{b^2-4ac}\\
\sqrt{b^2-4ac}=2ax+b\\
b^2-4ac=(2ax+b)^2\\
-4ac=4a^2x^2+4abx+b^2-b^2\\
-4ac=4a^2x^2+4abx\\
c=-ax^2-bx$