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NNADVOKAT [17]
3 years ago
6

Know how to calculate sample size: A restaurant would like to estimate the average $ amount of a take-out order. The standard de

viation is $15. If a 99% confidence level and an interval (error) of $5 is desired, how many customers should be in the sample?
Which of the following examples would use the z-distribution:______.
a. x = 100; µ = 99; s = 5; n = 70
b. x = 50; µ = 53; σ = 7; n = 15
c. x = 7; µ = 4; s = 1; n = 20
d. x = 15; µ = 17; σ = 3; n = 45
Mathematics
1 answer:
Ne4ueva [31]3 years ago
8 0
Easy it’s c duhhhhhhh girl it’s C
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A number, plus one-third of itself, plus one-eighth of itself, equals 70. What is the number?
Alex73 [517]
X - the number

x+\frac{1}{3}x+\frac{1}{8}x=70 \\
\frac{24}{24}x+\frac{8}{24}x+\frac{3}{24}x=70 \\
\frac{35}{24}x=70 \\
x=70 \times \frac{24}{35} \\
x=2 \times 24 \\
x=48

The number is 48.
3 0
4 years ago
-8/5 divide by -6/7 equals
tia_tia [17]
<span>-8/5 divide by -6/7 equals

(-8/5) / (-6/7)
= (-8/5) * (-7/6)
= 56/30
= 28/15
= 1 13/15</span>
4 0
3 years ago
Read 2 more answers
?? Can someone help me with this
OleMash [197]

choice B, D, F, and G are correct

4 0
3 years ago
Determine whether the two expressions are equivalent. If so, tell what property is applied.
Hoochie [10]

Answer:

I think its associative property but I am not sure.

Step-by-step explanation:

4 0
3 years ago
!50 POINTS! GIVE REAL ANSWER OR I REPORT PLZ NO TROLLS! An executive drove from his home at an average speed of 35 mph to an air
bixtya [17]

Answer:

it took him 3 hours to get to work

Step-by-step explanation:

For the first part of the trip, the executive covered a distance "d" in time 't" at 35 mph, therefore we can write that the time it took to get to the helicopter was:

t-\frac{d}{35}

which if the distance is in miles, will render the time in hours.

We can write something similar for the second part of the trip", using the same "t" since it took the same time as for the first one, and using for distance 169.5 - d (since it is the distance to complete the total traveled distance :

t=\frac{169.5-d}{78}

Now we equal those two equations because the time "t" is the same, and solve for "d":

\frac{d}{35} =\frac{169.5-d}{78} \\78\,d=35\,(169.5-d)\\78\,d=5932.5-35\,d\\(78+35)\,d=5932.5\\d=\frac{5932.5}{113} \\d=52.5

Now, knowing the distance covered in the first trip, we can find the time of that first trip:

t=\frac{52.5}{35} =1.5\,\,hours

Therefore, the time it took for thye total trip is: 1.5 h + 1.5 h = 3 hours

7 0
3 years ago
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