Using the data for each truck lets calculate,
median for truck 1 - 511.5
median for truck 2 - 650.5
lets consider each statement
A.medians for both trucks are the same - wrong
median for 1 and 2 are 511.5 and 650.5 respectively
B. the two trucks sold most number of tacos on 3rd day
truck 1 sold 437 on day 3 but highest number it sold was 721 on day 1
truck 2 sold 426 on day 3 but highest number was 732 on day 6
therefore this statement too is wrong
C.
truck 1 - range between maximum(721) and minimum(425) = 296
truck 2 - maximum (732) and minimum (426) difference = 306
the range between maximum and minimum in truck 2 is 306 thats greater than range between maximum and minimum in truck 1, that's 296
therefore this statement is correct
D.
total number of tacos for each truck -
truck 1 - 5291
truck 2 - 6107
food truck 1 sold less than truck 2 therefore this statement too is wrong
If a^2+b^2=c^2 then it's a right triangle
If c^2>a^2+b^2 then it's obtuse
If c^2< a^2+b^2 then it's acute
C - Fifteen and forty-five thousandths
Answer: <em>f(x) </em>= 21 .The output is 21 when the input is 5.
Step-by-step explanation:
f(x) = 4x+1 Substitute the input, 5, for x on the right side <em> f(x) is the equivalent of y, the output you are looking for</em>
<em>f(x) </em>= 4(5) + 1
<em>f(x) </em> = 20 +1
<em>f(x) </em>= 21
As far as I can tell is just a Permutation.
