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3 years ago

Please help! Graph the line for y+1=−3/5(x−4) on the coordinate plane. I just need help with the coordinates.

Mathematics

1 answer:

otez555 [7]3 years ago

5 0

Answer:

SLOPE: - 3/5

Y-INTERCEPT: 7/5

Step-by-step explanation: Check picture :)

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Question

Jobisdone [24]

Answer:

The light bulb will reach the ground 1.25 seconds after it is dropped.

Step-by-step explanation:

We know that for an object that is in the air, the only force acting on it will be the gravitational force (where we are ignoring the air resistance)

Then the acceleration of the object is the gravitational acceleration, 32.17 ft/s^2

Then the acceleration of the light bulb is:

A(t) = (-32.17 ft/s^2)

Where the negative sign is because the acceleration is downwards.

Now, to get the velocity equation, we need to integrate the acceleration over time, we will get:

V(t) = (-32.17 ft/s^2)*t + V0

Where V0 is the initial velocity of the light bulb. Because it is dropped, the initial velocity will be zero, then V0 = 0m/s, then the velocity equation is:

V(t) = (-32.17 ft/s^2)*t

Finally, to get the position equation we need to integrate again, we will get:

P(t) = (1/2)*(-32.17 ft/s^2)*t^2 + P0

Where P0 is the initial height of the object, and in this case, we know that it is equal to 25 ft.

Then the position equation is:

P(t) = (1/2)*(-32.17 ft/s^2)*t^2 + 25ft

The object will hit the ground when P(t) = 0 ft, then we need to solve that equation for t:

P(t) = (1/2)*(-32.17 ft/s^2)*t^2 + 25ft = 0 ft

25 ft = (1/2)*(32.17 ft/s^2)*t^2

2*25ft = (32.17 ft/s^2)*t^2

50ft = (32.17 ft/s^2)*t^2

√( 50ft/(32.17 ft/s^2)) = t = 1.25 s

The light bulb will reach the ground 1.25 seconds after it is dropped.

8 0

3 years ago

120 is 160% of what number?

oksian1 [2.3K]

If that number is x:

120 = 1.60x
x = 120/1.60=75

8 0

3 years ago

Read 2 more answers

The table below shows selected points from a function.

FrozenT [24]

Answer:

True

Step-by-step explanation:

Rate Of Change Of Functions

Given a function y=f(x), the rate of change of f can be computed as the slope of the tangent line in a specific point (by using derivatives), or an approximation by computing the slope of a secant line between two points (a,b) (c,d) that belong to the function. The slope can be calculated with the formula

$\displaystyle m=\frac{d-b}{c-a}$

If this value is calculated with any pair of points and it always results in the same, then the function is linear. If they are different, the function is non-linear.

Let's take the first two points from the table (1,1)(2,4)

$\displaystyle m=\frac{4-1}{2-1}=3$