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Anna007 [38]
3 years ago
14

Mr. Saba owns two food trucks. He rents two spots at the state fair. This table shows the number of tacos the two food trucks so

ld each day for 10 days.
Food Truck 1 721 658 437 527 601 468 425 431 508 515
Food Truck 2 462 471 426 654 647 732 701 684 632 698

Which conclusion can be drawn from the data?

The medians for the two taco trucks are the same
.
The two food trucks sold the most tacos on Day 3.

The range between the maximum and minimum values for taco truck 2 is greater than the range between the maximum and minimum values for taco truck 1.

On average, food truck 1 sold more tacos over the 10 days than food truck 2.
Mathematics
2 answers:
Nadya [2.5K]3 years ago
5 0
Using the data for each truck lets calculate, 

median for truck 1 - 511.5
median for truck 2 - 650.5

lets consider each statement 
A.medians for both trucks are the same - wrong 
median for 1 and 2 are 511.5 and 650.5 respectively 

B. the two trucks sold most number of tacos on 3rd day 
truck 1 sold 437 on day 3 but highest number it sold was 721 on day 1
truck 2 sold 426 on day 3 but highest number was 732 on day 6
therefore this statement too is wrong 

C.
truck 1 - range between maximum(721) and minimum(425) = 296
truck 2 - maximum (732) and minimum (426) difference = 306
the range between maximum and minimum in truck 2 is 306 thats greater than range between maximum and minimum in truck 1, that's 296
therefore this statement is correct

D.
total number of tacos for each truck - 
truck 1 - 5291
truck 2 - 6107
food truck 1 sold less than truck 2 therefore this statement too is wrong 
postnew [5]3 years ago
5 0

Answer: C)  The range between the maximum and minimum values for taco truck 2 is greater than the range between the maximum and minimum values for taco truck 1.

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The price of Stock A at 9 A.M. was ​$14.83. Since​ then, the price has been increasing at the rate of ​$0.12 each hour. At noon
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Answer:

  • 0.5 hours

Step-by-step explanation:

Let the x be the number of hours after noon.

<u>We have the following equation:</u>

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5 0
3 years ago
Suppose you drive a car 392 mi on a tank of gas. The tank holds 14 gallons. The number of miles traveled vaties directly with th
Serhud [2]

Preliminary Problem

Givens

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Formula

miles = miles per gallon * number of gallons.

Solve

392 = mpg * 14                         Divide by 14

392 / 14 = mpg

28 = mpg  which is really quite good.  Our vehicle gets 44 mpg but it's a 4 cylinder. It's meant to get that kind of milage.

Part A

Let x = the number of gallons used

Let y = the number of miles driven

y = k*x

Part B

y = k* x

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x = 417.86

If this is incorrect please put some more facts in. The question does not seem complete.


7 0
3 years ago
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ki77a [65]
Multiply both sides by 19 to get w=171
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