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Karolina [17]
3 years ago
7

Sixty-five ten thousandths

Mathematics
1 answer:
Vlada [557]3 years ago
6 0
0.0065 is how you say sixty-five ten thousandths
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During the cold winter months, a sheet of ice covers a lake near the Arctic Circle. At the beginning of spring, the ice starts t
Masja [62]

Answer: The ice sheet's thickness decrease every 6 weeks= 1.5 meters

Step-by-step explanation:

GIven: At the beginning of spring, the ice starts to melt. The variable sss models the ice sheet's thickness (in meters) t weeks after the beginning of spring. s=-0.25t+4

At t=0, s=4

So, Thickness of ice sheet at the beginning = 4 meters

Now at t= 6, we get

s=-0.25(6)+4=-1.5+4=2.5

Thickness of ice sheet after 6 weeks = 2.5 meters

Decrease in thickness = 4 meters - 2.5 meters = 1.5 meters

Hence, the ice sheet's thickness decrease every 6 weeks= 1.5 meters

3 0
3 years ago
Round 23.2736 to the nearest thousandth​
alekssr [168]

Answer:

23.274

Step-by-step explanation:

Here, rounding to the nearest thousandth means rounding to the nearest 0.001.

Hence, due to the digit being rounded having a number larger than 5 after it (0.2736), it is rounded up.

Hope this helped!

5 0
2 years ago
Erin clocked the top speed of her remote control car at 25 meters per second. Her brother Ben clocked the top speed of his remot
exis [7]

Sorry but..I don't even know where to start. Good luck!

4 0
3 years ago
I need the simplified expression for this please ​
Leto [7]
Here you go 15x-10/3

3 0
3 years ago
5.11.
irinina [24]

Answer:

Following are the response to the given points:

Step-by-step explanation:

For question 5.11:

For point a:

For all the particular circumstances, it was not an appropriate sampling strategy as each normal distribution acquired is at a minimum of 30(5) = 150 or 2.5 hours for a time. Its point is not absolutely fair if it exhibits any spike change for roughly 10 minutes.

For point b:

The problem would be that the process can transition to an in the state in less than half an hour and return to in the state. Thus, each subgroup is a biased selection of the whole element created over the last 2 \frac{1}{2} hours. Another sampling approach is a group.

For question 5.12:

This production method creates 500 pieces each day. A sampling section is selected every half an hour, and the average of five dimensions can be seen in a \bar{x}line graph when 5 parts were achieved.

This is not an appropriate sampling method if the assigned reason leads to a sluggish, prolonged uplift. The difficulty would be that gradual or longer upward drift in the procedure takes or less half an hour then returns to a controlled state. Suppose that a shift of both the detectable size will last hours 2 \frac{1}{2} . An alternative type of analysis should be a random sample of five consecutive pieces created every 2 \frac{1}{2} hour.

7 0
3 years ago
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