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belka [17]
3 years ago
5

Need Help please answer

Mathematics
1 answer:
djverab [1.8K]3 years ago
6 0
For the 2nd part of 2. just plug in what you have for G in your previous graph into the equation. This will give you H for all 5 columns . Like 3×8(-1+5)= h = 3× 32= 96 so H should equal 96 and so on as far as this function.

For number 3. The equation is given so just plug in your T for time which is 3 seconds, so...-16(3)^2+90(3) = H the height at 3 seconds. I'm doing it in my head but should be the height is 414. You should also say whether it's ft or inches etc because the teacher or yourself left that out of the equation which is also vital lol.
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Please I need help ASAP
givi [52]

Answer:

A. d = 1/10t

Step-by-step explanation:

2 = 20/10

4 = 40/10

6 = 60/10

3 = 30/10

5 0
3 years ago
22 is what percentage of 55%
Liula [17]

Answer:

12.1

Step-by-step explanation:

3 0
3 years ago
PLS HELP I HAVE LEGIT 20 MINUTES TO FINISH BY 11:59 IM PANICKING PLS HELP WITH THESE QUESTIONS
poizon [28]
I’m pretty sure it is 19.2 units
5 0
2 years ago
Read 2 more answers
A washer and dryer cost $803 combind the washer costs $47 less then the dryer whats is the cost of the dryer
Naddik [55]

Answer:

the dryer costs $425

Step-by-step explanation:

x = washer

y = dryer

x + y = 803

x = y - 47

using the second equation a substitute in the first equation we get

y - 47 + y = 803

2y = 850

y = $425

FYI

x = y - 47 = 425 - 47 = $378

3 0
3 years ago
Read 2 more answers
What is the sum of 20x^2-10x-30
ivann1987 [24]

Answer:

The sum of the roots is 0.5

Step-by-step explanation:

<u><em>The correct question is</em></u>

What is the sum of the roots of 20x^2-10x-30

we know that

In a quadratic equation of the form

ax^{2} +bx+c=0

The sum of the roots is equal to

-\frac{b} {a}

in this problem we have

20x^{2} -10x-30=0  

so

a=20\\b=-10\\c=-30

substitute

-\frac{(-10)} {20}=0.5

<u><em>Verify</em></u>

Find the roots of the quadratic equation

The formula to solve a quadratic equation is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

a=20\\b=-10\\c=-30

substitute

x=\frac{-(-10)\pm\sqrt{-10^{2}-4(20)(-30)}} {2(20)}

x=\frac{10\pm\sqrt{2,500}} {40}

x=\frac{10\pm50} {40}

x=\frac{10+50} {40}=1.5

x=\frac{10-50} {40}=-1

The roots are x=-1 and x=1.5

The sum of the roots are

-1+1.5=0.5 ----> is ok

5 0
3 years ago
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