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belka [17]
3 years ago
5

Need Help please answer

Mathematics
1 answer:
djverab [1.8K]3 years ago
6 0
For the 2nd part of 2. just plug in what you have for G in your previous graph into the equation. This will give you H for all 5 columns . Like 3×8(-1+5)= h = 3× 32= 96 so H should equal 96 and so on as far as this function.

For number 3. The equation is given so just plug in your T for time which is 3 seconds, so...-16(3)^2+90(3) = H the height at 3 seconds. I'm doing it in my head but should be the height is 414. You should also say whether it's ft or inches etc because the teacher or yourself left that out of the equation which is also vital lol.
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Which of these ordered pairs is a solution to the linear inequality 3y - 2x > 8?
Tanzania [10]
For this case we have the following inequality:
 3y - 2x> 8
 The first thing we should do is to graph the function.
 Then, see the set of points that are the solution of the inequality.
 The solution set is given by the shaded region.
 See attached image.
 Answer:
 
Shaded region.
 
See attached image.

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Find the sum. Write your answer in simplest form.
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the answer for your question is 9 31/42

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3 years ago
A pilot flew a 400 mile flight in 2.5 hours flying into the wind. Flying the same rate and with the same wind speed the return t
eduard

Answer: 20 mph

Explanation:

Speed is a physical quantity which is equal to the ratio between the distance covered (d) and the time taken (t):

v=\frac{d}{t}

In the first part of the problem, the plane flew a distance of d=400 mi in a time of t=2.5 h. The speed of the plane in this case was the difference between the proper speed of the plane, v, and the speed of the wind, w, since the plane flew opposite to the wind. So we can write:

v-w=\frac{400mi}{2.5h}=160 mph (1)

During the return trip, the plane flew with a speed (v+w), since the wind was on the tail, and it took 2 hours to cover the same distance:

v+w=\frac{400 mi}{2 h}=200 mph (2)

So we have two equations with two unknown variables. From (1), we get

v=160+w

Substituting into eq.(2)

(160+w)+w=200\\160+2w=200\\2w=40\\w=20 mph

So, the speed of the wind was 20 mph.

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3 years ago
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