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Harlamova29_29 [7]

4 years ago

6

Eleanor was curious if triangles DEF and GHI were similar, so he tried to map one figure onto the other using rigid transformati

ons Eleanor concluded "It's not possible to map triangle DEF on GHI using a sequence of rigid transformations, so the triangles are not similar.
What error did Eleanor make in her decision?
A. One more transformation- a rotation- would map triangle DEF onto GHI. So the triangles are similar
B. One more transformation- a dilation- would map triangle DEF onto GHI. So the triangles are similar.
C. There is no error. This is a correct conclusion

2 answers:

bixtya [17]4 years ago

7 0

Answer:

Step-by-step explanation:

Fiesta28 [93]4 years ago

4 0

Answer:B

Step-by-step explanation:

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The base of a solid is the region in the first quadrant bounded by the line x=-2y+6 and the coordinate axes. What is the volume

nika2105 [10]

Answer:

$V = \frac{4y^3}{3} -12y^2 +36 y \Big|_0^3$

$V= \frac{4(3)^3}{3} -12(3)^2 +36 (3) -0 = 36-108+108= 36$

Step-by-step explanation:

For this case we have the following plot on the figure attached.

We know on this case that $x = -2y+6$ represent our radius for the square, since we need cross sections perpendicular to the y axis.

We find the intersection points like this:

$x= 0 , y=3$

$y=0, x=6$

Since we are assuming squares for the cross sections the area is given by $A = r^2$ where r = x= -2y+6.

Since our radius is on terms of x we can create a integral with limits on x in order to find the volume, And we can use the following integral in order to find the volume.

$V = \int_{0}^3 (-2y+6)^2 = \int_{0}^3 4y^2 -24y +36 dy$

On the left part we are using the following property from algebra:

$(a+b)^2 = a^2 +2ab +b^2$

$(-2y+6)^2 = (-2y)^2 +2*(-2y)(6) +(6)^2 = 4y^2 -24y+36$

And after do the integral we got this:

$V = \frac{4y^3}{3} -12y^2 +36 y \Big|_0^3$

$V= \frac{4(3)^3}{3} -12(3)^2 +36 (3) -0 = 36-108+108= 36$

7 0

3 years ago

Simplify<br><br> 1/4(1-2/3)^2+1/3<br><br> answer as a simplified fraction

BlackZzzverrR [31]

Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

May someone help me with this problem? Thank you!

Aleks04 [339]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Let's find the value of given expression for x = 5 ~

$\qquad \sf \dashrightarrow \:3(3x + 5)$

$\qquad \sf \dashrightarrow \:9x + 15$

now, plug in the value of x as 5

$\qquad \sf \dashrightarrow \:9(5) + 15$

$\qquad \sf \dashrightarrow \:45 + 15$

$\qquad \sf \dashrightarrow \:60$

so, the equivalent value is 60

6 0

2 years ago

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If the measurement of a central angle is 5π/6, find the length of its intercepted arc in a circle with a radius of 15 inches.

Artist 52 [7]

Answer: d. 39.3 inches

Step-by-step explanation:

Given the measurement of central angle ( $\frac{5\pi}{6}$ ) and the measure of radius (15 inches), the lenght of the intercepted arc in the circle can be calculated with the formula:

$arc\ length=r\theta$

Where r represents the radius of the circle and $\theta$ the central angle.

Substituting $\theta=\frac{5\pi}{6}$ and $r=15inches$ into the formula $arc\ length=r\theta$ :

$arc\ length=(15inches)(\frac{5\pi}{6})\\arc\ length=39.3inches$

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3 years ago