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olchik [2.2K]
3 years ago
5

!!!!!!!!!!!!!!!!!!!!!!!!!PLEASE HELP!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
denis-greek [22]3 years ago
5 0

Answer:

-t2+10t-h+8  = 0

Step-by-step explanation:

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Find the difference. express the answer in scientific notation. (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 sup
Georgia [21]

The difference between (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 superscript 11 baseline) is 1. 43 × 10^11

<h3>How to determine the notation</h3>

Given the expression

(5. 29 × 10^11) - (3. 86 × 10 ^11)

First, find the common factor

10^11 ( 5. 29 - 3. 86)

Then substract the values within the bracket

10^11 (1. 43)

Multiply with the factor, we have

⇒1. 43 × 10^11

Thus, the difference between (5.29 times 10 superscript 11 baseline) minus (3.86 times 10 superscript 11 baseline) is 1. 43 × 10^11

Learn more about index notation here:

brainly.com/question/10339517

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2 years ago
How do i do this problem 0.25(x+4)-3=28
KiRa [710]
Distribute the .25 to get .25x + 1 - 3 = 28

Then simplify to get .25x - 2 = 28

Move the two to the right to get .25x = 30

Then divide to leave x: 30 / .25 = 120

X = 120
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3 years ago
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How can a solution to a system of linear equations be determined exactly by graphing?
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A solution something something and that’s the answer
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What is the common difference for the sequence shown below?
Nezavi [6.7K]

we can always find the slope of any line by simply using two points on the line, say let's  use (3,4) and (-1,2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{2}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{2-4}{-1-3}\implies \cfrac{-2}{-4}\implies \stackrel{\stackrel{\textit{common difference}}{\downarrow }}{\cfrac{1}{2}}

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Can anyone help me with this page i can’t find the answers
Dvinal [7]

1) f(x)=2x

when x=3 then f(x) =3×2=<em><u>6</u></em>

when x=4 then f(x)=4×2=<em><u>8</u></em>

2)At y=35(no. of mangoes),x corresponds to y=60(amount)

so$<em><u>6</u></em><em><u>0</u></em><em><u>,</u></em><em><u> </u></em><em><u>amount</u></em><em><u> </u></em><em><u>he</u></em><em><u> </u></em><em><u>need</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>spend</u></em><em><u>!</u></em>

3) f(x)= x+2

for x=1, f(x)=1+2=<em><u>3</u></em>

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