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stepladder [879]

3 years ago

7

J- 7.5 = 16.937 ????

1 answer:

Leviafan [203]3 years ago

8 0

Add 16.937 and 7.5. It's basically doing the problem backwards.

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Which one is greater 5 or 1.5

Andrew [12]

Answer:

5

Step-by-step explanation:

5 is greater than 1.5 by 3.5

5 - 1.5 = 3.5

~

8 0

2 years ago

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The mean of a set of eight numbers is 8 and the mean of a different set of twelve numbers is m. Given that the mean if the combi

Basile [38]

Mean=total/the number of values =>total=mean*the number of values
the total of the first set of 8 numbers is : total=8*8=64
the total of the second set of 12 numbers is: 12m
the total of the 20 numbers is: 64+12m
the mean of the 20 number is: (64+12m)/20=5
solve for m: 64+12m=100
12m=36
m=3

8 0

3 years ago

If x+3/3 = y+2/ 2 , then x/3 = _____.

iren [92.7K]

the question is not so clear

is it (x+3)/3 or what you have written is correct

Step-by-step explanation:

4 0

2 years ago

PLASE ANSWER THIS QUESTION I GIVE YOU 18 POINTS

sukhopar [10]

Answer:

(a) 144

(b) 117

(c) 360

(d) 588

(e) 5472

Step-by-step explanation:

To find the LCM of two numbers, first find the prime factorization of each number. Then the LCM is the product of common and not common factors with the larger exponent.

2.

(a)

$72 = 2^3 \times 3^2$

$144 = 2^4 \times 3^2$

$LCM = 2^4 \times 3^2 = 8 \times 9 = 144$

(b)

$39 = 3 \times 13$

$117 = 3^2 \times 13$

$LCM = 3^2 \times 13 = 117$

(c)

$72 = 2^3 \times 3^2$

$90 = 2 \times 3^2 \times 5$

$LCM = 2^3 \times 3^2 \times 5 = 360$

(d)

$84 = 2^2 \times 3 \times 7$

$147 = 3 \times 7^2$

$LCM = 2^2 \times 3 \times 7^2 = 588$

(e)

$152 = 2^3 \times 19$

$288 = 2^5 \times 3^2$

$LCM = 2^5 \times 3^2 \times 19 = 5472$

6 0

2 years ago

Find all numbers whose absolute value is -5.

Kryger [21]

There are none. Absolute values are always positive

3 0

3 years ago

Read 2 more answers