Question

I need help now plz​

Answer 1

Answer:

C

Step-by-step explanation:

The picture is a bit blurry, but from what i can see, i'd say C (whichever one has -4 x 3 x 1 under the square root.)

So for this, you need to know the quadratic formula, which is:

$\frac{-b ± \sqrt{b^{2} -4ac} }{2a}$

*ignore the weird capital A, it keeps coming up when i try to use the ± symbol

They have given you the equation of a quadratic, so the first thing you have to do is rearrange it, so that $x^{2}$ comes first.

So now we have the equation: 3$x^{2}$ - 2x +1

*the quadratic formula uses a, b and c, but they are specific. a is always the coefficient of $x^{2}$ , b is always the coefficient of x and c is always the constant (number without an x)

So, i can find that, in this case:

a = 3      b= -2    c=1

Now substitute each of those values it into the original quadratic equation:

$\frac{-(-2) ± \sqrt{(-2)^{2} -4(3)(1)} }{2(3)}$

*again, ignore the weird capital A.

That's how you find the answer, which from what i can tell in the picture is C.

Hope that helped : )