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3 years ago

8 to the thrid power

Mathematics

2 answers:

artcher [175]3 years ago

8 0

Its 512

p.s. spread le cheese ⌂

Lisa [10]3 years ago

7 0

Hey there!

8 to the 3rd power means you multiply the number 8 three times:

8 x 8 = 64

64 x 8 = 512

512 is your final answer <------------

Hope this helps you.
Have a great day!

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I need help plz help me

Andrej [43]

Answer:

Step-by-step explanation:

It appears to be the last step there that has evaded you. In the second line of work, you can see that what's in each set of parenthesis is exactly the same. Because of this, it is common and can be factored out. What's left is the 4x and the +5:

(5x - 3)(4x + 5)

That's factoring by grouping. It only works with polynomials that have an even number of terms so you can group them together in 2's.

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4 years ago

If the table shows the equation y = x/3 ,what is the missing value? x y 21 7 15 ? 6 2 A. 6 B. 5 C. 4 D. 3

Naddik [55]

Answer:

the answer B. 5

4 0

3 years ago

Read 2 more answers

Question 10 of 10

Alika [10]

9514 1404 393

Answer:

D. y = -1/3x

Step-by-step explanation:

The line through the origin means the equation will be a proportion of the form y = kx. (You can also see this by looking at the answer choices.) The value of k is ...

k = y/x . . . . . divide the above equation by x

For the given point (x, y) = (-3, 1), the value of k can be seen to be ...

k = 1/-3 = -1/3

Then the equation for the line is ...

y = -1/3x . . . . matches D

6 0

3 years ago

When 1,250 Superscript three-fourths is written in simplest radical form, which value remains under the radical?

Dvinal [7]

The value remains under the radical is 8 ⇒ last answer

Step-by-step explanation:

Let us revise how to write the exponent as a radical

$a^{\frac{m}{n}}$ can be written as $\sqrt[n]{a^{m}}$
To simplify the radical factorize the base "a" to its prime factors

Example:

$(54)^{\frac{2}{3}}=\sqrt[3]{(54)^{2}}$ ,
Factorize 54 into prime factors ⇒ 54 = 2 × 3 × 3 × 3 = $2(3)^{3}$
$\sqrt[3]{(54)^{2}}=\sqrt[3]{[2(3^{3}]^{2}}=\sqrt[3]{2^{2}*3^{6}}$
2² can not go out the radical because 2 is less than 3 not divisible by 3
$3^{6}$ can go out the radical because 6 is divisible by 3, then divide 6 by 3, so it will be 3² out the radical
$\sqrt[3]{(54)^{2}}=3^{2}\sqrt[3]{2^{2}}=9\sqrt[3]{4}$

Now let us solve your problem

∵ $1250^{\frac{3}{4}}=\sqrt[4]{1250^{3}}$

- Factorize 1250 to its prime factors

∵ 1250 = 2 × 5 × 5 × 5 × 5

∴ $1250=2*5^{4}$

∴ $\sqrt[4]{(2*5^{4})^{3}}=\sqrt[4]{2^{3}*5^{12}}$

∵ 2³ can not go out the radical because 3 < 4 and not divisible by it

- $5^{12}$ can go out the radical because 12 can divided by 4

∵ 12 ÷ 4 = 3

∴ $5^{12}$ can go out the radical as 5³

∴ $\sqrt[4]{1250}=5^{3}\sqrt[4]{2^{3}}$

∴ $\sqrt[4]{1250}=125\sqrt[4]{8}$

∴ The value remains under the radical = 8

The value remains under the radical is 8

Learn more:

You can learn more about the radicals in brainly.com/question/7153188

#LearnwithBrainly

8 0

3 years ago

The two box plots summarize the number of hours spent in the weight room for all the players on the football team

iragen [17]

Options:

A. Players at school 1 typically spent more time in the weight room than players at school 2.

B. The middle half of the data for school 1 has more variability than the middle half of the data for school 2.

C. The median hours spent in the weight room for school 1 is less than the median for school 2 and the interquartile ranges for both schools are equal.

D. The total number of hours spent in the weight room for players at school 2 is greater than the total number of hours for players at school 1.

(See attachment for the box plots)

Answer:

C. The median hours spent in the weight room for school 1 is less than the median for school 2 and the interquartile ranges for both schools are equal.

Step-by-step explanation:

The median for school 1 is the value at the vertical line that divides the box of the box plot display of for school 1, which is 8

School 2 has a median of 9.

As we can see, the median for school 1 is less than the median of school 2.

Interquartile range is the range of the box.

Interquartile range for school 1 = 10 - 4 = 6

Interquartile range for school 2 = 13 - 6 = 6

As we can also see, the interquartile range for school 1 and that of school 2 are equal.

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4 years ago