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Marat540 [252]
3 years ago
15

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

Mathematics
2 answers:
shtirl [24]3 years ago
8 0

Answer:

first Q . mirror

Second Q. sight and touch

erma4kov [3.2K]3 years ago
7 0

Answer:    Smoothest surface: mirror

senses being used: sight and touch

hope this helps!

Step-by-step explanation:

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An engineering crew ran several tests on a new automobile engine they were designing. The mean fuel consumption was 52.4 miles p
zhenek [66]

Any value which is more than 2 standard deviations away from the mean is considered to be "unusual."  

2 standard deviations above the mean 52.4 mp would be 52.4+2(1.8), or 56; 2 std devs below the mean would be 52.4 - 2(1.8), or 48.8.  Thus, any value larger than 56 or any value smaller than 48.8 would be "unusual."

54.8, 49.1 and 51.3 are not unusual; 56.5 is unusual, because it's greaster than 56.

8 0
3 years ago
What is the remainder of 5x^2 - 3x - 36 divided by x - 3
lidiya [134]

Answer:

5x^-3x-36/x-3

Step-by-step explanation:

3 0
3 years ago
Students in Ms. Singh's class had the following scores on their last quiz.
Svetllana [295]
the median of her 20 students is 82.5
8 0
2 years ago
X^2+3x−10=0 (solve for x)
kap26 [50]

Answer:

x1=2 x2=-5

Step-by-step explanation:

7 0
2 years ago
The average daily volume of a computer stock in 2011 was ų=35.1 million shares, according to a reliable source. A stock analyst
Shtirlitz [24]

Answer:

a

   The  null hypothesis is  H_o :  \mu =  35 .1 \ million  \ shares

    The  alternative hypothesis  H_a  :  \mu  \ne  35.1\ million  \ shares

b

 The   95% confidence interval is  27.475   <  \mu < 37.925

Step-by-step explanation:

From the question the we are told that

      The  population mean is  \mu  = 35.1 \  million \ shares

      The  sample size is  n = 30

       The  sample mean is  \= x  =  32.7 \ million\    shares

       The standard deviation is  \sigma =  14.6 \ million\  shares

     

Given that the confidence level is  95\% then the level of significance is mathematically represented as

                  \alpha  = 100-95

                  \alpha  = 5\%

=>               \alpha  = 0.05

Next we obtain the critical value of \frac{\alpha }{2} from the normal distribution table

    The value is  Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as

                 E  =  Z_{\frac{\alpha }{2} } *  \frac{ \sigma }{\sqrt{n} }

substituting values

                E  =  1.96 *  \frac{ 14.6 }{\sqrt{30} }

                E  =  5.225

The 95% confidence interval confidence interval is mathematically represented as

              \= x  -E  <  \mu <  \= x  +E

substituting values

               32.7 - 5.225   <  \mu < 32.7 + 5.225

                27.475   <  \mu < 37.925

       

6 0
3 years ago
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