Answer:
C) He will temporarily have less money in his bank account.
Explanation:
Since Philip is going to spend $600 in his motorcycle repairs, he will have less money in his bank account.
We cannot know where he is going to drive his motorcycle or what he is going to do with his free time. If the repairs are done properly then he mght be able to either keep the motorcycle for a little longer or sell it for a higher price. We also don't know what he plans to do.
The only thing certain is that he is going to have less money.
Answer:
<u>(a) as either fixed or variable</u>
fixed
Coolants for machinery
Annual flat fee paid for factory security
Machinery depreciation (straight-line)
Taxes on factory
variable
Lace to hold leather together
Wages of assembly workers
Leather covers for soccer balls
<u>(b) as either direct or indirect</u>
direct
Lace to hold leather together
Wages of assembly workers
Leather covers for soccer balls
indirect
Coolants for machinery
Annual flat fee paid for factory security
Machinery depreciation (straight-line)
Taxes on factory
Explanation:
Fixed Costs are constant for any production level. Variable Costs vary directly with production.
Direct Costs are easily traced to the product manufactured. Indirect costs are not easily traced and they need to be allocated to Products manufactured.
Answer:
$4,600
Explanation:
Standard rate = $0.60
Unit produced = 9,000
Favorable spending variance = $800
Material spending variance = [Standard rate - Actual rate) * Unit produced
Material spending variance = [Standard rate*Unit produced - Actual rate*Unit produced
$800 = [$0.6*9000) - Actual cost
Actual cost = [$0.6*9000) - $800
Actual cost = $5,400 - $800
Actual cost = $4,600
Answer:
Aquaguard may choose any of the two models to minimize the production variability in the new plant.
Explanation:
Model 1: Mean = 1000, Standard Deviation(SD) = 300
Model 2: Mean = 1000, SD = 300
Model 3: Mean = 1000, SD = 300
Coefficient of variation for model 1
C.V = ( SD ÷ Mean) × 100
= ( 300 ÷ 1000 ) × 100
= 30 %
Coefficient of variation for model 2
= ( 300 ÷ 1000 ) × 100
= 30 %
Coefficient of variation for model 3
= ( 300 ÷ 1000 ) × 100
= 30 %
We conclude that all the models have same effect .
