Answer:
Given- O is the centre of a circle in which an equilateral ΔPQR has been inscribed.
To find out- ∠QOR=?
Solution- The points P, Q & R are on the circumference of the circle since ΔPQR has been inscribed in the circle. Now the chord QR subtends ∠QOR to the centre O and ∠QPR to the circumference at P.
∴ By rule, ∠QOR=2∠QPR.........(i).
Now PQR is an equilateral Δ. Each of its angle is 60
o
. i.e ∠QPR=60
o
.
So, from (i), ∠QOR=2∠QPR=2×60
o
=120
o
.
Ans- Option B.
solution
Answer:
do u have a picture or smth? there is not enough info
6 3/7 multiplied by 21 is 135. Your answer is C. 135 <span />
Answer:
It's b. 100
Step-by-step explanation:
10 x 10= 100 = rational number, other include a series of numbers that cannot be written down.
Sorry if this is wrong hope I did the math right. :)
.394= 197/500
you can't make it a mixed number since there isn't a whole number as with an improper fraction.
