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Marianna [84]
3 years ago
6

Please help! Find the area and the perimeter of the shaded regions below. Give your answer as a completely simplified exact valu

e in terms of π (no approximations). The figures below are based on semicircles or quarter circles and problems b), c), and d) are involving portions of a square. Please answer with your work, explanation, and answers to perimeter and area to the shaded region.

Mathematics
1 answer:
Nadya [2.5K]3 years ago
5 0

Answer:

The \ area \ of \ the \ figure = 4\dfrac{1}{2} \cdot \pi + 18 \ cm^2

Step-by-step explanation:

Given that the figure is made up of portion of a square and a semicircle, we have;

BC ≅ AB = 6 cm

The area of semicircle BC with radius BC/2 = 3 is 1/2×π×r² = 1/2×π×3² = 4.5·π cm²

Triangle ABC = 1/2 × Area of square  from which ABC is cut

The area of triangle ABC = 1/2×Base ×Height = 1/2×AB×BC = 1/2×6×6 = 18 cm²

The area of the figure = The area of semicircle BC + The area of triangle ABC

The area of the figure = 4.5·π cm² + 18 cm² = \dfrac{9 \cdot \pi +36}{2} \ cm^2.

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Hey there!

-2<3x+1

= 3x + 1 < -2

SUBTRACT 1 to BOTH SIDES

3x + 1 - 1 < -2 + 1

CANCEL out: 1 - 1 because that gives you 0

KEEP: -2 + 1 because that helps you solve for x

-2 + 1 = -3

New EQUATION: 3x > -3

DIVIDE 3 to BOTH SIDES

3x/3 > -3/3

CANCEL out: 3/3 because that gives you 1

KEE3 -3/3 because that helps us compare for x

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Answer to the equation: x > -1

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8 0
2 years ago
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Answer:

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4 0
3 years ago
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3 years ago
Which of the following is equal to the fraction below?
Vesna [10]

In mathematics there is a rule of exponents where we can "distribute" the powers/exponents in the numerator and denominator of any expression. Therefore, given an expression as (\frac{a}{b})^n, the exponent n can be "distributed" as: (\frac{a}{b})^n= \frac{a^n}{b^n}.

In our case, the power, n=11; a=7 and b=4. Thus, the expression (\frac{7}{4})^{11}, can be written as \frac{7^{11}}{4^{11}}.

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6 0
3 years ago
Read 2 more answers
Find all integers $n$ for which $\frac{n^2+n+1}{n-1}$ is an integer.
Grace [21]
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