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2 years ago

Sara made 8 necklaces. She used 9 beads on each necklace. The beads came in bags of 6 each. How many bags

Mathematics

1 answer:

motikmotik2 years ago

4 0

Answer:

12 bags

Step-by-step explanation:

9×8=72 beads all together

72/6=12 bags of beads

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Ben bought a movie ticket for $37.50. He got $12.50 for change. How much was the ticket?

Tom [10]

Answer:

$25

Step-by-step explanation:

37.50-12.50=$25.00

6 0

3 years ago

Read 2 more answers

Peter threw the football 72 feet. How many yards did he throw the football ?

Darya [45]

1 yard = 3 feet.

Divide total feet by 3 to get yards:

72 feet / 3 = 24 yards.

3 0

3 years ago

Explain the error a student is asked to find when the value of an investment of $5200 is an account that earns 4.2% annual inter

zloy xaker [14]

We are given the following information

Investment = $5200

Annual interest rate = 4.2% = 0.042

Final amount = $16,500

Number of years = 27.7 years

Number of compoudings = quartely = 4

The student uses the following model

$V(t)=5200(1.014)^{3t}$

The general formula for compound interest is given by

$V(t)=P(1+\frac{r}{n})^{nt}$

As you can see, the number of compoundings is incorrect (3 vs 4)

The interest rate is also incorrect.

Let us substitute the given values into the above formula

$\begin{gathered} V(t)=P(1+\frac{r}{n})^{nt} \\ V(t)=5200(1+\frac{0.042}{4})^{4\cdot27.7} \\ V(t)=5200(1+0.0105)^{110.8} \\ V(t)=5200(1.0105)^{110.8} \\ V(t)=\$16543.5^{} \end{gathered}$

Therefore, the final amount is approximately $16,543.5

5 0

1 year ago

Given that lim x → 2 f ( x ) = 1 lim x → 2 g ( x ) = − 4 lim x → 2 h ( x ) = 0 limx→2f(x)=1 limx→2g(x)=-4 limx→2h(x)=0, find the

VashaNatasha [74]

Answer:

According what I can read, I have the following statements:

$\lim_{x \to 2} f(x) = 1$

$\lim_{x \to 2} g(x) = -4$

$\lim_{x \to 2} h(x) = 0$

a) Applying properties of limits

$\lim_{x \to 2} f(x) + 5g(x) = \lim_{x \to 2} f(x) + 5 \lim_{x \to 2} g(x) = 1 + 5*-4 = -19$

b) Applying properties of limits

$\lim_{x \to 2} g(x)^{3} = {(\lim_{x \to 2} g(x))}^{3} = (-4)^{3} = -64$

c) Applying properties of limits

$\lim_{x \to 2} \sqrt{f(x)} = \sqrt{\lim_{x \to 2} f(x)} = \sqrt{1} = 1$

d) Applying properties of limits

$\lim_{x \to 2} 4*g(x)*f(x) = 4*\lim_{x \to 2} g(x)*\lim_{x \to 2} f(x) = 4*-4*1 =-16$

e) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x) = -4*0 =0$

f) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x)*f(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x)*\lim_{x \to 2} f(x = -4*0*1 =0$

3 0

3 years ago

The reactants of two reactions are shown.

katovenus [111]

Answer:

The answer to your question is letter B.

Step-by-step explanation:

The correct answer is letter B because both Copper and Iron as reactants have an oxidation number of zero and when they have reacted their oxidation numbers would be different from those.

A redox reaction is a reaction that involves a transfer of electrons from one atom to another and the oxidation numbers of the reactants are different from the oxidation numbers from the products.

4 0

3 years ago