Hello,
the first step should be to distribue:
-4(3-5x)= -12+20x
Teh resolution may be:
-4(3-5x)>=-6x+9
==>-12+20x>=-6x+9
==>20x+6x>=9+12
==>26x>21
==>x>=21/26
But an other way may be used:
-4(3-5x)>=-6x+9
==>3-5x<= -6x/(-4)+9/(-4)
==>-5x-3/2 x<=-9/4 -3
==>-13/2 x <=-21/4
==>x>= -21/4 *(-2/13)
==>x>=21/(2*13)
==>x>=21/26
B I think but i could be totally wrong
Answer:
i have no clew
Step-by-step explanation:
Answer:
<h2>x =
-2+i√5 and -2i-√5</h2>
Step-by-step explanation:
The general form of a quadratic equation is ax²+bx+c = 0
Given the quadratic equation x²+4x+9=0 in its standard form, on comparing with the general equation we can get the value of the constant a, b and c as shown;
ax² = x²
a = 1
bx = 4x
b = 4
c = 9
The quadratic formula is given as x = -b±√(b²-4ac)/2a
Substituting the constant;
x = -4±√(4²-4(1)(9))/2(1)
x = -4 ±√(16-36)/2
x = -4±√-20/2
x = -4±(√-1*√20)/2
Note that √-1 = i
x = -4±(i√4*5)/2
x = (-4±i2√5)/2
x = -4/2±i2√5/2
x = -2±i√5
The solution to the quadratic equation are -2+i√5 and -2i-√5
If<span> the degree </span>measure<span> of </span>two<span> complementary </span>angles<span> are in the ratio of </span>1<span>:14, ... These are similar to complementary </span>angles<span>, except </span>their<span> sum is </span>180<span> degrees. ... </span>1<span> = </span>angle 3<span>, (because they are vertical </span>angles<span>), </span>then<span> the </span>measure<span> of </span>angle 3<span> = y - 5.</span>
