What is the area of this parallelogram PLEASE HELP QUICKLY!!!20 points!!!
2 answers:
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Answer:
Here's what I get.
Step-by-step explanation:
9. (6, -8)
The reference angle θ is in the fourth quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100
OB = √100 = 10
10. cot θ = -(√3)/2
The reference angle θ is in the second quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7
OB = √7
Answer:
see below
Step-by-step explanation:
dilation with a scale factor of 1/3 means the distances to the center shrink by 1/3
so for center (4,-2)
distance of (7,4) is 3 n 6 to center
1/3 of distance = 1 n 2
so (7,4) become (4+1, -2+2) = (5, 0) after the dilation
similarly u can find the other 2 pts
distance of (-2,4) is -6 n 6 to center
1/3 of distance = -2 n 2
so (-2,4) become (4-2, -2+2) = (2, 0) after the dilation
distance of (1, 10) is -3 n 12 to center
1/3 of distance = -1 n 4
so (1,10) become (4-1, -2+4) = (3, 2) after the dilation
plot the new triangle using the 3 pts
