Answer:
I think it's 3
Step-by-step explanation:
To calculate the gradient equals to
y(1)-y(2)
-----------
x(1)-x(2)
So - 5 - 1 = - 6
6 - 2 = 4
-6 - 3
--- = ----- x
4 2
And the first y intercept is 1 so I guess it's 3.
Just for refernece, not sure if I'm correct. Sry
Answer:
The best point of estimate for the true mean is:

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.
Step-by-step explanation:
Information given
represent the sample mean for the late time for a flight
population mean
represent the population deviation
n=76 represent the sample size
Confidence interval
The best point of estimate for the true mean is:

The confidence interval for the true mean is given by:
(1)
The Confidence level given is 0.95 or 95%, th significance would be
and
. If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got
Replacing we got:
Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.
Answer:
- y = 50·3^x
- (2, 450), (3, 1350), (4, 4050), (5, 12150)
Step-by-step explanation:
The problem statement tells you each observed count is 3 times the last one.
__
Expressed as an exponential function with an initial value of 50 and a growth factor of 3, the formula is ...
y = (initial value)×(growth factor)^x
y = 50·3^x
B because the 2 is in the hundredths place and then you look behind the 2 which is a 5.
If its five or more you go up and 4 or less you go down, which means that you add one to the 2 which is 3 and you get rid of anything behind the 3 that was the originally.