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3 years ago

Find the surface area of the square pyramid below.

Mathematics

1 answer:

valentina_108 [34]3 years ago

4 0

Answer:

728 m^2

Step-by-step explanation:

There are 5 faces of the square pyramid.

You have to calculate area of each face and add them to find surface area.

Bottom face is a square, so

area = 14^2 = 196 m^2

All the other faces are triangle with same area, so

4 × triangle area

4 × ((1/2)×14×19)

4 × 133

532 m^2

Now add those areas,

(196 + 532) m^2

728 m^2

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Dr. Oswald conducts a study examining the relationship between the number of friends one has and the experience of daily stress

Alina [70]

Answer:

I believe the answer is: These scores are more likely to have an effect because of the large sample size

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6 0

2 years ago

Number 4. Please help

IgorLugansk [536]

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2 years ago

At an amusement park , the cost of 3 adult tickets and 4 children’s ticket is $126.50 another customer paid $120.50 for 2 adult

KonstantinChe [14]

Answer:

1 Adult ticket=$21.50 ; 1 Children ticket=$15.50

Step-by-step explanation:

3A+4C=126.50

2A+5C=120.50

We find the price of adult tickets 1st.

15A+20C=632.5

8A+20C=482

7A=632.5-482=150.5

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Now we find Children ticket

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4 0

3 years ago

Find a formula for the described function. A rectangle has perimeter 16 m. Express the area A of the rectangle as a function of

Alex17521 [72]

Part A:

Let the length of one of the sides of the rectangle be L, then the length of the other side is obtained as follow.

Let the length of the other side be x, then

$2(L+x)=16 \\ \\ \Rightarrow L+x=8 \\ \\ \Rightarrow x=8-L$

Thus, if the length of one of the side is x, the length of the other side is 8 - L.

Hence, the area of the rectangle in terms of L is given by

$L(8 - L) = 8L-L^2$

Part B:

To find the domain of A

Recall that the domain of a function is the set of values which can be assumed by the independent variable. In this case, the domain is the set of values that L can take.

Notice that the length of a side of a rectangle cannot be negative or 0, thus L cannot be 8 as 8 - 8 = 0 or any number greater than 8.

Hence the domain of the area are the set of values between 0 and 8 not inclusive.

Therefore,

$dom(Area)=0\ \textless \ L\ \textless \ 8 \ or \ (0, 8)$

3 0

3 years ago

Are the two expressions equivalent 5(3x+8) 8x+8 when x=10

Brums [2.3K]

Answer:no

Step-by-step explanation:

5(3(10)+8)

5(30+8)

5(38)=190

8(10)+8

80+8

88≠190 so no

7 0

3 years ago

Read 2 more answers