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3 years ago

7

Are opposite sides parallel in a cyclic quadrilateral ?

1 answer:

faust18 [17]3 years ago

5 0

Electronegativity<span> is a measure of the tendency of an atom to attract a bonding pair of electrons. The Pauling scale is the most commonly used. Fluorine (the most</span>electronegative<span> element) is assigned a value of 4.0, and values range down to caesium and francium which are the least </span>electronegative<span> at 0.7.</span>

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almond37 [142]

12/3 is rational

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3 years ago

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The average car decreases in value by about 15% per year. If a car's original value is $28,000, which function best represents i

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Step-by-step explanation:

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3 years ago

Find the y-intercept of the graph.

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2 years ago

Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its average number of unoc

Bingel [31]

Answer:

We need a sample size of at least 719

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?

This is at least n, in which n is found when $M = 0.3, \sigma = 4.103$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.3 = 1.96*\frac{4.103}{\sqrt{n}}$

$0.3\sqrt{n} = 1.96*4.103$

$\sqrt{n} = \frac{1.96*4.103}{0.3}$

$(\sqrt{n})^{2} = (\frac{1.96*4.103}{0.3})^{2}$

$n = 718.57$

Rouding up

We need a sample size of at least 719

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2 years ago

A survey of 25 grocery stores revealed that the mean price of a gallon of milk was $2.98, with a standard error of $0.10. What i

Gnesinka [82]

Answer:

95% confidence interval: (2.784,3.176)

Step-by-step explanation:

We are given the following information in the question:

Sample size, n = 25

Sample mean = $2.98

Standard error = $0.10

Alpha = 0.05

95% confidence interval:

$\mu \pm z_{critical}(\text{Standard error})$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

$2.98 \pm 1.96(0.10) = 2.98 \pm 0.196 = (2.784,3.176)$

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2 years ago