How do you simplify the expression -2(3v+3)+6v

Find the area of each trapezoid, rhombus, or kite.

Rus_ich [418]

Answer:

15 is the area

Step-by-step explanation:

8 0

3 years ago

The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly

Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between $\\ (\mu - 6\sigma)$ and $\\ (\mu + 6\sigma)$ . It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

$\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027$

For those with defects operating at a 6 sigma level, the probability is:

$\\ 1 - p = 1 - 0.999999998027 = 0.000000001973$

Similarly, for finding no defects in a 5 sigma level, we have:

$\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697$ .

The probability of defects is:

$\\ 1 - p = 1 - 0.999999426697 = 0.000000573303$

Well, the defects present in a six sigma level and a five sigma level are, respectively:

$\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}$

$\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}$

Then, comparing both fractions, we can confirm that a 6 sigma level is markedly different when it comes to the number of defects present:

$\\ {6\sigma} \approx \frac{2}{10^9}$ [1]

$\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9}$ [2]

Comparing [1] and [2], a six sigma process has 2 defects per billion opportunities, whereas a five sigma process has 600 defects per billion opportunities.

8 0

3 years ago

John’s father is 5 times older than John and John is twice as old as his sister Alice. In two years time, the sum of their ages

oksano4ka [1.4K]

Answer:

8 years

Step-by-step explanation:

Let age of father be f

age of John be j

age of Alice be a

John's father is 5 times as old as John. We can write:

f = 5j

John is twice as old as Alice. We can write:

j = 2a

or

a = j/2

SUM OF ALL OF THEIR AGES (after 2 years) will be 58. We can write:

f+2 + j+2 + a+2 = 58

This becomes:

f + j + a + 6 = 58

f + j + a = 52

Now, we replace third equation with the first two (in bold) and get:

$f + j + a = 52\\5j + j + \frac{1}{2}j=52\\6.5j=52\\j=8$

So John is 8 years old

7 0

3 years ago

Triangle ABC has coordinates of A(–8, –8), B(4, –2), and C(2, 2). Find the coordinates of its image after a dilation centered at

kherson [118]

The answer is (C) because you multiply each point by 1.5.

7 0

3 years ago

Read 2 more answers

Find the sum. Express your answer in simplest form.

Marina86 [1]

Answer:

$\frac{10x^2+3}{y^2+4}$

Step-by-step explanation:

When adding rational numbers, if the denominator is the same you simply keep the denominator (bottom of fraction) as it is and apply the operation given to the numerator ( top of fraction )

So we have $\frac{6x^2+5}{y^2+4} +\frac{4x^2-2}{y^2+4} =\frac{(6x^2+5)+(4x^2-2)}{y^2+4}$