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3 years ago

5

The experimental probability of getting a 6 on a number cube is StartFraction 7 over 40 EndFraction. Which is true about the eve

nt's experimental probability?

2 answers:

Semenov [28]3 years ago

7 0

Answer:

the number 6 appeared 7 times out of 40

Step-by-step explanation:

Ghella [55]3 years ago

3 0

Answer:

the answer is A

Step-by-step explanation:

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A normal distribution has a mean of 4 and a standard deviation of 1. What percent of values are from 4 to 7?

Igoryamba

Answer:

49.865%

Step-by-step explanation:

Given that:

μ = 4 ; σ = 1

For x = 4

P(x < 4) :

Z score (x - μ) / σ

P(x < 7) - P(x < 4)

((7 - 4) / 1) - ((4 - 4) / 1)

P(Z < 3) - P(Z < 0)

Usibg the Z probability calculator :

0.99865 - 0.5

= 0.49865

= 0.49865 * 100

= 49.865%

6 0

3 years ago

HELP BEFORE TOMORROW PLZZZ (show how to solve it plz)

Zepler [3.9K]

40/1.4=28.57 i think this is right

6 0

3 years ago

What is 75% of 24?<br><br> Thanks!

FrozenT [24]

18 i looked it up hope its right

5 0

3 years ago

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Evaluate the diagram below. Find the measures of Angles A, B, C, and D.

laiz [17]

Answer:

A: 65° B: 65° C: 125° D: 125°

Step-by-step explanation:

It is an equilateral(shown by the two dashes) and all angles in a triangle add up to 180°.

180-50 divided by 2 to give you A and B angles.

Then angled on a straight line add up to 180° so if you take angle A away from 180° you will get the answer to angle C.

The same for angle D.

5 0

3 years ago

A mass suspended from a spring is raised a distance of 5 cm above its resting position. The mass is released at time t=0 and all

miskamm [114]

Rates of change are the change of a quantity over another.

The rate of change of the mass position at 2.1 seconds is -89.6 cm/ s

The given parameters are:

$\mathbf{A = |5|}$ -- the amplitude

$\mathbf{T = \frac 13}$ --- the period

The position of the mass is modeled by:

$\mathbf{y= Acos(wt)}$

Where:

$\mathbf{w = \frac{2\pi }{T}}$

So, we have:

$\mathbf{w = \frac{2\pi}{1/3}}$

$\mathbf{w = 6\pi }$

$\mathbf{y= Acos(wt)}$ becomes

$\mathbf{y = |5|cos(6\pi t)}$

$\mathbf{y = 5cos(6\pi t)}$

Differentiate

$\mathbf{y' = 5 \times -sin(6\pi t) \times (6\pi)}$

$\mathbf{y' = -30\pi sin(6\pi t) }$

When t = 2.1, we have:

$\mathbf{y' = -30\pi sin(6\pi \times 2.1) }$

$\mathbf{y' = -30\pi sin(12.6\pi) }$

$\mathbf{y' = -30\pi \times 0.9510}$

$\mathbf{y' = -89.6296}$

Approximate

$\mathbf{y' = -89.6}$

Hence, the rate of change of the mass position at 2.1 seconds is -89.6 cm/ s

Read more about rates at:

brainly.com/question/15579510

6 0

3 years ago

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