If you want the answer in point slope form then,
y-y1 = m(x-x1)
y-c = m(x-a)
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If you want the answer in slope intercept form, then solve for y
y-c = m(x-a)
y-c = mx-ma
y-c+c = mx-ma+c
y = mx-ma+c
y = mx+c-ma
y = mx+(c-ma)
For this answer in slope intercept form the slope is m and the y intercept is c-ma
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If you want the answer in standard form, then get the variable terms to the left side. Have the constant terms on the right side.
y = mx+c-ma
y-mx = mx+c-ma-mx
-mx+y = c-ma
Optionally you can multiply both sides by -1 to get mx-y = -c+ma but it will depend on your book if this step is carried out or not.
The area of a triangle is 1/2(base)(height) and since this is a right triangle the two legs can be base and height. So the area is 1/2(2x-4)^2 which becomes 1/2(4x^2-16x+16) which is simplified to 2x^2-8x+8. B is the correct answer.
Answer:
Step-by-step explanation:
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Answer:
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Step-by-step explanation:
