All categories

2 years ago

Which of the following is equal to the expression below?

Mathematics

1 answer:

I am Lyosha [343]2 years ago

5 0

Answer:

cuteboy979409

Step-by-step explanation:

I am sorry mam a was not able to answer this question.

You might be interested in

Given vectors

Bogdan [553]

Answer:

option 2, 3, and 5

Step-by-step explanation:

yuh

7 0

2 years ago

I think i found the right one but I let her go thru my things but she wont lemme go thru her stuff what does that mean :( I want

Naily [24]

Answer:

she is ether hiding something. or she just wants you to respect her privacy and she is trying to see how much you trust her so she can figure out how much she can trust you. i say you should just tell her you don't care what she does to just do what she would want and then let her actions decide whether she realy cares abought or respects yall's relationship. maby put it in kinder words than did tho or you might just pi22 her off

Step-by-step explanation:

the 22 is ss i just dont want to get banned

8 0

2 years ago

Read 2 more answers

What is 18 times 40 to the 9th power

Rzqust [24]

I believe thugs is it
4.718592e+15

3 0

3 years ago

Read 2 more answers

Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En

Sergio [31]

Answer:

$\bold{cot(t) =\dfrac{12}{5}}$

Step-by-step explanation:

Given that:

$Cosec (t) = -\frac{13}5$

for $\pi < t < \frac{3 \pi}2$

That means, angle $t$ is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

$cosec^2\theta -cot^2\theta =1$

here, $\theta =t$

So, $cosec^2t-cot^2t=1$

$\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}$

But, angle $t$ is in 3rd quadrant, so value of

$\bold{cot(t) =\dfrac{12}{5}}$

4 0

3 years ago

An engineering student answered 58 questions correctly on a 100-question trigonometry test.

finlep [7]

If you are trying to find the percentage he received: 58/100

Total correct divided by total questions.

You get .58 or

58% by moving the decimal to spaces to the right.

6 0

2 years ago