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3 years ago

A box of small crackers holds 4 equal servings. If there are 124 crackers in the box, how many crackers are in each serving?

2 answers:

7 0

For this equation, we can simply divide the box's total (124) by 4 servings. 124/4 = 31. So, there is 31 crackers per serving.

elena55 [62]3 years ago

5 0

Answer:

B). 31 crackers

Step-by-step explanation:

Just took the unit test :P

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Mr. Abraham is 36 years old. His wife is 6 years younger than him and their son is 24 years old younger than his wife. What is t

sesenic [268]

Hi!
We know that Mr. Abraham’s wife is 6 years younger than him, which is 36-6, which means his wife is 30 years old.

We also know that Mr A’s son is 24 years younger than his wife, which is 30-24, which is 6.

As of right now, we now know that:
Mr. A is 36
Mr. A’s wife is 30
Mr. A’s son is 6

It’s asking for the ratio of Him:Wife:Son, so 36:30:6.

BUT, it’s asking for simplest form, so divide each of those numbers by 6.

Your answer is: 6:5:1

8 0

3 years ago

For the function given, state the middle line; f(t) = 40cos (80t + 20)

Digiron [165]

In the standard form of the equation

$\\ \ f(t)=Acos[b(t\pm c)]+k\\ \\$

The middle line =k

For our given problem

f(t) = 40cos (80t + 20)

On comparison we get k=0

Hence middle line=0

8 0

3 years ago

Applications: Sarah's Pet Store never has more than a combined total of 16 cats and dogs. She also never has more than 9 cats. W

ankoles [38]

The possible solution is 12 cats and 4 dogs in Sarah's store.

Let x represent the number of cats and y represent the number of dogs.

Since Sarah's Pet Store never has more than a combined total of 16 cats and dogs. Hence:

x + y ≤ 16

Also, She also never has more than 9 cats. Therefore:

x > 9

The solution to the inequality is graphed. From the graph, the possible solution is 12 cats and 4 dogs

Find out more on inequalities at: brainly.com/question/24372553

4 0

3 years ago

F-20f=21 what’s the answer

Virty [35]

$\bold{[ \ Answer \ ]}$

$\boxed{\bold{F \ = \ -\frac{21}{19} }}$

$\bold{[ \ Explanation \ ]}$

$\bold{Solve: \ f \ - \ 20f \ = \ 21}$

-----------------------------------

$\bold{Add \ Similar \ Elements:f-20f=-19f}$

$\bold{-19f=21}$

$\bold{Divide \ Both \ Sides \ By \ -19}$

$\bold{\frac{-19f}{-19}=\frac{21}{-19}}$

$\bold{Simplify}$

$\bold{F \ = \ -\frac{21}{19}}$

$\boxed{\bold{[] \ Eclipsed \ []}}$

5 0

3 years ago

90 POINTS! HELP PLEASE!!!! I need answers to a-e thank you.

polet [3.4K]

Answer:

(a)Equation representing amount of lights on Monday is 2 x + 3 y = 44

(b)Equation representing amount of lights on Tuesday is 5 x + 3 y = 56

(c) Bob uses 4 stands of light on Bushes

and Bob uses 12 strands of lights on trees.

Step-by-step explanation:

Let x = strands of lights on bushes.

Let y = strands of lights on trees.

Bob used 44 strands of light to decorate 2 bushes and 3 trees on Monday.

So, the number of light on 2 bushes = 2x

and the number of light on 3 tress = 3 y

⇒ 2 x + 3 y = 44

Also, On Tuesday, Bob used 56 strands of lights to decorate 5 bushes and 3 trees.

So, the number of light on 5 bushes = 5x

and the number of light on 3 tress = 3 y

⇒ 5 x + 3 y = 56

Now, solving the system of equations:

2 x + 3 y = 44

5 x + 3 y = 56

Subtract equation (2) from (1), we get

2 x + 3 y - (5 x + 3 y) = 44 - 56

or, 2x - 5x = - 12

or, 3x = 12 ⇒ x = 12/3 = 4 or x = 4

Using x = 4 in 2x + 3y = 44

2(4) + 3y = 44

or, 3y = 44- 8 = 36

or y = 36 /3 = 12 or y = 12

So, the value of x = 4, and y = 12

Hence, here Bob uses 4 stands of light on Bushes

and Bob uses 12 strands of lights on trees.

8 0

3 years ago