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Yanka [14]
3 years ago
10

90 POINTS! HELP PLEASE!!!! I need answers to a-e thank you.

Mathematics
1 answer:
polet [3.4K]3 years ago
8 0

Answer:

(a)Equation representing amount of lights on Monday is 2 x  + 3 y = 44

(b)Equation representing amount of lights on Tuesday is 5 x  + 3 y = 56

(c) Bob uses 4 stands of light on Bushes

    and Bob uses 12 strands of lights on trees.

Step-by-step explanation:

Let x = strands of lights on bushes.

​Let y = strands of lights on trees.

Bob used ​44 strands of light to decorate 2 bushes and 3 trees on Monday.

So, the number of light on 2 bushes  = 2x

and  the number of light on 3 tress  = 3 y

⇒ 2 x  + 3 y = 44

Also, On Tuesday, ​Bob used 56 strands of lights to decorate 5 bushes and 3 trees.

So, the number of light on 5 bushes  = 5x

and  the number of light on 3 tress  = 3 y

⇒ 5 x  + 3 y = 56

Now, solving the system of equations:

2 x  + 3 y = 44

5 x  + 3 y = 56

Subtract equation (2) from (1), we get

2 x  + 3 y  - (5 x  + 3 y)  = 44   - 56

or, 2x - 5x = - 12

or, 3x  =  12 ⇒ x =  12/3  = 4    or x  = 4

Using x  = 4 in 2x + 3y = 44

2(4)  + 3y  =  44

or, 3y = 44- 8 = 36

or y = 36 /3 = 12 or y  = 12

So, the value of x  = 4, and y = 12

Hence, here Bob uses 4 stands of light on Bushes

and Bob uses 12 strands of lights on trees.

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Answer:

Step-by-step explanation:

for 1st week=1 ¢

for 2nd week= 2¢

for 3rd week= 4¢

for 4th week=8¢

for 5th week=16¢

for 6th week=32¢

for 7th week=64¢

for 8th week=64+64=128¢

for 9th week= 128+128=256¢

for 10th week= 256+256=512¢

.: he saved a total of

1+2+4+8+16+32+64+128+256+512=1023¢

1023¢=1023/100=$10.23

4 0
3 years ago
A person's blood glucose level and diabetes are closely related. Let x be a random variable measured in milligrams of glucose pe
soldier1979 [14.2K]

Using the normal distribution, it is found that:

a) 0.8599 = 85.99% probability that x is more than 60.

b) 0.1788 = 17.88% probability that x is less than 110.

c) 0.6811 = 68.11% probability that x is between 60 and 110.

d) 0.0643 = 6.43% probability that x is greater than 125.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of 87, thus \mu = 87.
  • The standard deviation is of 25, thus \sigma = 25.

Item a:

This probability is <u>1 subtracted by the p-value of Z when X = 60</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 87}{25}

Z = -1.08

Z = -1.08 has a p-value of 0.1401.

1 - 0.1401 = 0.8599

0.8599 = 85.99% probability that x is more than 60.

Item b:

This probability is the <u>p-value of Z when X = 110</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{110 - 87}{25}

Z = 0.92

Z = 0.92 has a p-value of 0.8212.

1 - 0.8212 = 0.1788.

0.1788 = 17.88% probability that x is less than 110.

Item c:

This probability is the <u>p-value of Z when X = 110 subtracted by the p-value of Z when X = 60</u>.

From the previous two items, 0.8212 - 0.1401 = 0.6811.

0.6811 = 68.11% probability that x is between 60 and 110.

Item d:

This probability is <u>1 subtracted by the p-value of Z when X = 125</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{125 - 87}{25}

Z = 1.52

Z = 1.52 has a p-value of 0.9357.

1 - 0.9357 = 0.0643.

0.0643 = 6.43% probability that x is greater than 125.

A similar problem is given at brainly.com/question/24863330

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Fifty-four is what<br> % of 60.
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Answer:

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Step-by-step explanation:

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Interpreting composite functions in the real world The volume of air in a balloon is represented by the function v(r)=4/3 ³, whe
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There are two <em>true</em> statements:

  1. When the function is composed with r, the <em>composite</em> function is V(t) = (1/48) · π · t⁶.
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<h3>How to use composition between two function</h3>

Let be <em>f</em> and <em>g</em> two functions, there is a composition of <em>f</em> with respect to <em>g</em> when the domain of <em>f</em> is equal to the range of <em>g</em>. In this question, the <em>domain</em> variable of the function V(r) is replaced by substitution.

If we know that V(r) = (4/3) · π · r³ and r(t) = (1/4) · t², then the composite function is:

V(t) = (4/3) · π · [(1/4) · t²]³

V(t) = (4/3) · π · (1/64) · t⁶

V(t) = (1/48) · π · t⁶

There are two <em>true</em> statements:

  1. When the function is composed with r, the <em>composite</em> function is V(t) = (1/48) · π · t⁶.
  2. V(r(6)) shows that the volume is 972π cubic inches after 6 seconds.

To learn on composition between functions: brainly.com/question/12007574

#SPJ1

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