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Jlenok [28]
3 years ago
15

The sum of three consecutive even integers is 378. what is the largest of the three integers

Mathematics
1 answer:
Oksana_A [137]3 years ago
3 0
It is 128. the sum of the three even integers are 124 + 126 + 128 =378. 128 is the largest. hope this helped.
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The half-life of a radioactive isotope is the time it takes for a quantity of the isotope to be reduced to half its initial mass
Sauron [17]

Answer:

Quantity remaining= 27.5 grams

Step-by-step explanation:

If the initial quantity of the radioactive isotope= 220 grams

And for each half life it will reduce to half of its original quantity

For first half life

Quantity= 220/2

Quantity= 110 grams

Now for the second half life , the quantity to work with will be 110 grams

Second half life

Quantity= 110/2

Quantity= 55 grams

For the third half life , the quantity to work with is 55 grams

Third half life

Quantity= 55/2

Quantity= 27.5 grams

So after 3 half life's of this radioactive isotope, the amount remaining out of 220 = 27.5 grams.

Another simple way to do this

Since half life reduce the isotope by half of its original.

The third half life will reduce it by (1/2)^3= 1/8

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Quantity remaining= 27.5 grams

6 0
3 years ago
A rocket carrying fireworks is launched from a hill 60 feet above a lake. The rocket will fall into the lake after exploding at
castortr0y [4]

Answer:

<h3>A) 204m</h3><h3>B) 188m</h3>

Step-by-step explanation:

Given the rocket's height above the surface of the lake given by the function h(t) = -16t^2 + 96t + 60

The velocity of the rocket at its maximum height is zero

v = dh/dt = -32t + 96t

At the maximum height, v  = 0

0 = -32t + 96t

32t = 96

t = 96/32

t = 3secs

Substitute t = 3 into the modeled function to get the maximum height

h(3) = -16(3)^2 + 96(3) + 60

h(3) = -16(9)+ 288 + 60

h(3) = -144+ 288 + 60

h(3) = 144 + 60

h(3) = 204

Hence the maximum height reached by the rocket is 204m

Get the height after 2 secs

h(t) = -16t^2 + 96t + 60

when t = 2

h(2) = -16(2)^2 + 96(2) + 60

h(2) = -64+ 192+ 60

h(2) = -4 + 192

h(2) = 188m

Hence the height of the rocket after 2 secs is 188m

3 0
3 years ago
6 ⅔ × (-5 ¹/¹⁶) ___answer​
olya-2409 [2.1K]
I got 24 as the answer to ur question
6 0
3 years ago
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Harlamova29_29 [7]

Answer:

\frac{3}{2}

Step-by-step explanation:

3 0
3 years ago
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ludmilkaskok [199]
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