Question

(x 4 - 3x 3 + 3x 2 - 3x + 6) (x - 2)

Answer 1

Answer:

x^5 - 5 x^4 + 9 x^3 - 9 x^2 + 12 x - 12

Step-by-step explanation:

(x ^4 - 3x^3 + 3x^2 - 3x + 6) (x - 2)

Distribute the x to all the terms in the first parentheses

(x^ 4  *x - 3x^ 3  *x + 3x^ 2   *x - 3x   *x + 6*x)

Then simplify

(x^5 - 3x^4 + 3x^ 3 - 3x2 + 6x)

Distribute the -2 to all the terms in the first parentheses

(x^ 4  *(-2) - 3x^ 3  *(-2) + 3x^ 2   *(-2) - 3x   *(-2) + 6*(-2))

Then simplify

(-2x^4 +6x^3 -6x^ 2 +6x -12)

Add the terms together

(x^5 - 3x^4 + 3x^ 3 - 3x2 + 6x) +(-2x^4 +6x^3 -6x^ 2 +6x -12)

x^5 - 5 x^4 + 9 x^3 - 9 x^2 + 12 x - 12