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Anit [1.1K]
3 years ago
15

Arrange the following numbers in order fromleast to greatest.3.5, -1/4,-2 3/4 0,1​

Mathematics
1 answer:
Rama09 [41]3 years ago
3 0

Answer:

-2, -1/4, 0.1, 3/4, 3.5

Step-by-step explanation:

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Find three consecutive interferes whose sum is 96
Ronch [10]

Answer:

31, 32, 33

Step-by-step explanation:

x + x + 1 +x + 2 = 96

3x + 3 = 96

      -3    -3

3x = 93

/3     /3

x = 31

31 is the first number, so since they’re consecutive, the second two numbers are 32 and 33.

6 0
3 years ago
How many tens are in 1290
lozanna [386]

Answer:

129

Step-by-step explanation:

Divide 1290 by 10 and you get 129

3 0
3 years ago
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The vertices of triangle QRS have coordinates Q(1, −2), R(3, −2), and S(2, −4).
Mamont248 [21]
The vertices of triangle QRS have coordinates Q(1, −2), R(3, −2), and S(2, −4). The coordinates are the coordinates of the vertices of triangle QꞌRꞌSꞌ when triangle QRS is reflected across the x-axis <span>Qꞌ(1, 2), Rꞌ(3, 2), Sꞌ(2, 4). The answer is  letter B.</span>
6 0
3 years ago
as a contractor to make a hole 4 5/8 inches diameter. express the mixed number as an improper fraction.
san4es73 [151]

The mixed number as an improper fraction is 37/8

<h3>How to express the mixed number as an improper fraction?</h3>

The diameter is give as:

Diameter = 4 5/8

Next we convert the above number to an improper fraction

The numerator is calculated as

Numerator = 8 * 4 + 5

This gives

Numerator = 37

Hence, the mixed number as an improper fraction is 37/8

Read more about fractions at:

brainly.com/question/18734292

#SPJ1

7 0
1 year ago
What is the nth term?
kumpel [21]

Let a_k denote the <em>k</em>th term of the sequence. Then

a_k=a_1+d(k-1)

where <em>d</em> is the common difference between consecutive terms in the sequence and <em>a</em>₁ is the first term.

The sum of the first <em>n</em> terms is

S_n=\displaystyle\sum_{k=1}^na_k=a_1+a_2+\cdots+a_{n-1}+a_n

From the formula for a_k, we get

S_n=\displaystyle\sum_{k=1}^n(a_1+d(k-1))=a_1\sum_{k=1}^n1+d\sum_{k=1}^n(k-1)

S_n=\displaystyle na_1+d\sum_{k=0}^{n-1}k

S_n=na_1+\dfrac{d(n-1)n}2

S_n=\dfrac n2(2a_1-d+dn)

So we have d=-5, and 2a_1-d=16 so that a_1=\frac{11}2.

Then the <em>n</em>th term in the sequence is

a_n=\dfrac{11}2-5(n-1)=\boxed{\dfrac{21-10n}2}

7 0
3 years ago
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