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4 years ago

5

Please Help!!!!!

2 answers:

Rus_ich [418]4 years ago

6 0

You have to set these up in proportions to solve these problems. Then cross multiply and divide.

1. 3 = 15
12 = x

3x = 15 * 12
3x = 180
x = 180 ÷ 3
x = 60

Answer: 12 miles in 60 minutes (B)

2. 366 = 6
427 = x

366x = 427 * 6
366x = 2562
x = 2562 ÷ 366
x = 7

Answer: 427 miles in 7 hours (C)

Ludmilka [50]4 years ago

4 0

1) you have to multiply both sides by 4.
4x3= 12. 15x4= 60.
Therefore, it will take him 60 minutes to run 12 miles.

2) Terry drives at 61 miles per hour. 427/61= 7. Therefore, it will take him 7 hours to drive 427 miles.

Hope this helps :)

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Answer:

Step-by-step explanation:

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2 years ago

Which expression shows (3*100)+(5*10)+(5*1/10) in standard form?

Ivenika [448]

Answer:

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3 years ago

what is the volume of a oblique cylinder with the height of 6 cm and a 4 cm as the radius of its base

JulsSmile [24]

Answer :

301.44 cm³

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Explanation :

We know,

${ \longrightarrow \qquad\pmb {\boldsymbol{ Volume_{(cylinder)} = \pi {r}^{2} h \: }}}$

Where,

<em>r</em> is the radius of the cylinder. Here, the radius is 4 cm

<em>h</em> is the height of the cylinder. Here, height is 6 cm

Here, we will take the value of π as 3.14 approximately .

⠀

Substituting the values in the formula :

⠀

${ \longrightarrow \qquad{ \ { \sf{ Volume_{(cylinder)} \it {= 3.14 \times ({4})^{2} \times 6 \: }}}}}$

⠀

${ \longrightarrow \qquad{ \ { \sf{ Volume_{(cylinder)} \it {= 3.14 \times 16\times 6 \: }}}}}$

⠀

${ \longrightarrow \qquad{ \ { \sf{ Volume_{(cylinder)} \it {= 3.14 \times 96 \: }}}}}$

⠀

${ \longrightarrow \qquad{ \ { \it{ \pmb{ Volume_{(cylinder)} {= 301.44 \: }}}}}}$

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Therefore,

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6 0

3 years ago

Read 2 more answers

11. Write the balanced equation for the reaction of HC2H3O2, with Al(OH)3 to form H2O and Al(C2H302)3:

Kamila [148]

Answer:

74.36 g of aluminium acetate.

730.27g of aluminium acetate.

- to the nearest hundredth.

Step-by-step explanation:

Acetic acid is usually written as CH3COOH.

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So 6 moles of acetic acid produce 1 mole of aluminium acetate.

Using the molecular masses

6*( 1.008*4 + 12.011*2 + 16 *2) g acetic acid gives (26.98+3(36.032+ 2*12.011)

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= 74.36 g of aluminium acetate.

b.

(26.98 + 3*16 + 3 * 1.008) g of Al(OH)3 gives 207.142 g Al acetate

78.004 g gives 207.142 g Al acetate

275 g gives (207.142 / 78.004) * 275

= 730.27g Al acetate.

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4 years ago

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sukhopar [10]

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3 years ago