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Serga [27]
3 years ago
13

Please help me asap!!!

Mathematics
2 answers:
ivanzaharov [21]3 years ago
6 0
4/5 is .8 and 8/10 is .8 so the constant rate of change is .8
Nat2105 [25]3 years ago
3 0

Answer:

the length is double the number of months.

Step-by-step explanation:

You might be interested in
What is the value of x
kirza4 [7]
The value of X = 10. A is the answer. You will equate the denominator by multiplying by the numerator and eventually you will get you answer which is 10
8 0
3 years ago
A small publishing company is planning to publish a new book. The production costs will include one-time fixed costs (such as ed
zhuklara [117]

Answer:

For the cost from the two methods to be equal, 3,200 books have to be produced

Step-by-step explanation:

In this question, we are asked to calculate the number of books that will be produced for two methods of production having different fixed and variable costs to have the same production cost.

Since the number of books is something we do not know, let’s represent it with a variable called c.

For the first production method, the cost of production will be ; 58,881 + 8.50c

For the second production method, the cost of production will be; 18,081 + 21.25c

Now since they are said to be equal, we proceed to equate both;

58,881 + 8.5c = 18,081 + 21.25c

58,881-18,081 = 21.25c - 8.5c

40,800 = 12.75c

c = 40,800/12.75

c = 3,200 books

4 0
2 years ago
Three times a number, x, increased by four is equal to five times the number, x. Which equation can be used to solve for x?
Dimas [21]
3x+4=5x
4=5x-3x
4=2x
X=2
4 0
2 years ago
Read 2 more answers
7 | 3 + T | + 8 < 43
ziro4ka [17]

Answer:

T<7

Step-by-step explanation:

21+7T+8<43

29+7T<43

7T<43‒29

7T<14

7T/7<14/7

T<7

i think it is clear &i hope it helps you

3 0
3 years ago
Mr. Smith traveled to a city 300 miles from his home to attend a meeting. Due to car trouble, his average speed returning was 6
Kryger [21]

Answer: The speed at which he traveled to the city is 69.8 mph

Step-by-step explanation:

Let x represent the speed at which he traveled to the city.

Mr. Smith traveled to a city 300 miles from his home to attend a meeting.

Time = distance/speed

Time taken to travel to the city is

300/x

Due to car trouble, his average speed on returning was 6 mph less than his speed going. This means that the speed at which he returned is (x - 6) mph. Time taken to return from the city is

300/(x - 6)

If the total time for the round trip was 9 hours, it means that

300/x + 300/(x - 6) = 9

Cross multiplying by x(x - 6), it becomes

300(x - 6) + 300x = 9x(x - 6)

300x - 1800 + 300x = 9x² - 54x

9x² - 54x - 300x - 300x - 1800 = 0

9x² - 654x -1800 = 0

Applying the general quadratic equation,

x = [- b ± √(b² - 4ac)]/2a

From the equation given,

a = 9

b = - 654

c = 1800

Therefore,

x = [- - 654 ± √(- 654² - 4 × 9 × 1800)]/2 × 9

x = [654 ± √(427716 - 64800)]/18

x = [654 ± √362916.4]/18

x = (654 + 602.4)/2 or x = (654 - 602.4)/18

x = 1256.4/18 or x = 51.6/18

x = 69.8mph or x = 2.9 mph

The speed at which he traveled to the city is 69.8 mph

By checking,

Time spent travelling to the city = 300/69.8 = 4.3 hours

Time spent returning =

300/(69.8 - 6) = 4.7 hours

4.3 + 4.7 = 9 hours

3 0
3 years ago
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