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3 years ago

10

Which representation has a constant variation of -2.5?

1 answer:

TiliK225 [7]3 years ago

6 0

35 I know this because I’m guessing just because I wanna

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A helicopter hovers 1250 feet

jok3333 [9.3K]

Create a right triangle.

The height of the leg will be 1250 feet. We are given an angle of depression of 47°, so we can draw an imaginary line parallel to the base of the triangle.

By the AIA Theorem, the angle of the bottom right side of the right triangle will be 47 degrees.

We want to find the distance between the coast and the island. In other words, find the length of the base of the triangle. We can do so with trigonometric ratios.

tan47 = 1250/x

x = 1166.

8 0

3 years ago

In the geometric sequence below, what is the common ratio?<br><br> Sequence: 64,16,4,1

Elanso [62]

9514 1404 393

Answer:

1/4

Step-by-step explanation:

The common ratio is the ratio of successive terms:

16/64 = 4/16 = 1/4

The common ratio is 1/4.

4 0

2 years ago

HELPPP Plzzzzzzzzzz ASAP

Pepsi [2]

12*6 = 72 - (3*4) = 60 - (4*5) = 40

3 0

3 years ago

Read 2 more answers

The double number line shows the price of 1 cupcake.

mr Goodwill [35]

5 cupcakes = $7.5
18 cupcakes = $27

4 0

3 years ago

AM is a median in △ABC (M∈ BC ). A line drawn through point M intersects AB at its midpoint P. Find areas of △APC and △PMC, if A

Snowcat [4.5K]

Answer:

The area of APC is 70m². The area of triangle PMC is 35m².

Step-by-step explanation:

Let the area of triangle ABC be x.

It is given that AM is median, it means AM divides the area of triangle in two equal parts.

$\text{Area of }\triangle ACM=\text{Area of }\triangle ABM=\frac{x}{2}$ .....(1)

The point P is the midpoint of AB, therefore the area of APC and BPC are equal.

$\text{Area of }\triangle APC=\text{Area of }\triangle BPC=\frac{x}{2}$ ......(2)

The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.

$\text{Area of }\triangle APM=\text{Area of }\triangle BPM=\frac{x}{4}$ .....(3)

The area of triangle APM is 35m².

$\text{Area of }\triangle APM=\frac{x}{4}$

$35=\frac{x}{4}$

$x=140$

Therefore the area of triangle ABC is 140m².

Using equation (2).

$\text{Area of }\triangle APC=\frac{x}{2}$

$\text{Area of }\triangle APC=\frac{140}{2}$

$\text{Area of }\triangle APC=70$

Therefore the area of triangle APC is 70m².

Using equation (3), we can say that the area of triangle BPM is 35m² and by using equation (2), we can say that the area of triangle BPC is 70m².

$\triangle BPC=\triangle BPM+\triangle PMC$

$70=35+\triangle PMC$

$35=\triangle PMC$

Therefore the area of triangle PMC is 35m².

8 0

3 years ago