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goldfiish [28.3K]
3 years ago
14

What is the value of x

Mathematics
1 answer:
Effectus [21]3 years ago
7 0
4x+2x=180
6x= 180
Divide by 6
X= 30
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3x-1/5=x+1/3 pls help me
RoseWind [281]

Answer:

x=4/15

Step-by-step explanation:

first you need to make common denominators for 1/5 and 1/3

the common denominator is 15

5*3=15, 3*5=15. 1*3=3, 1*5=5

new equation:3x-3/15=x+5/15

now subtract x from both sides: 3x-3/15=x+5/15

                                                     -x          -x

                                                     2x-3/15=5/15

now you can add 3/15 to 5/15

2x=8/15

now for the last step, divide by 2 because there are 2 x's

2x/2=x         8/15 /2=4/15

x=4/15

8 0
1 year ago
Read 2 more answers
Laura and Chase wants to go to a baseball game. But, the tickets cost $300 each. Laura only had $20 left because she went shoppi
Natalija [7]

Answer:

No they don’t have enough money

Step-by-step explanation:

No:

54+20=74=that’s not enough

211+189=400

Thats enough but they’re are two of them so it would only be enough for one of them

I HOPE THIS IS WHAT YOU’RE LOOKING FOR AND IF NOT THEN I’M SO SO SORRY

5 0
3 years ago
Solve for 19= -3a -5
Vesnalui [34]

Answer:

a = -8

Step-by-step explanation:

19 = -3a - 5

Add 5 to both sides.

24 = -3a

Divide both sides by -3.

-8 = a

Switch sides.

a = -8

6 0
3 years ago
Read 2 more answers
How do the graphs of the functions f(x) = (Three-halves)x and g(x) = (Two-thirds)x compare?
miss Akunina [59]

Answer:

The answer to this question can be defined as follows:

Step-by-step explanation:

Given:

\bold{f(x)= (\frac{3}{2})^x}\\\\\bold{g(x)= (\frac{2}{3})^x}\\

Following are the graph attachment to this question:

The second function, that is g(x)= (\frac{2}{3})^x is not even a function.

Remember that g(x) function is the inverted f(x) function. And when you see this pattern, a reflection on the Y-axis expects you.

Reflection in the axis.

In x-axis:

Increase the function performance by -1 to represent an exponential curve around the x-axis.

In y-axis:

Increase the input of the function by -1 to represent the exponential function around the y-axis.

8 0
3 years ago
Read 2 more answers
I NEED HELP PLEASE, THANKS! :)
marissa [1.9K]

Answer:

x = 28.01t,

y = 10.26t - 4.9t^2 + 2

Step-by-step explanation:

If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -

x = ( 30 cos 20° )( time ),

y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2

To determine " ( 30 cos 20° )( time ) " you would do the following calculations -

( x = 30 * 0.93... = ( About ) 28.01t

This represents our horizontal distance, respectively the vertical distance should be the following -

y = 30 * 0.34 - 4.9t^2,

( y = ( About ) 10.26t - 4.9t^2 + 2

In other words, our solution should be,

x = 28.01t,

y = 10.26t - 4.9t^2 + 2

<u><em>These are are parametric equations</em></u>

5 0
3 years ago
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