Given:
square with sides measuring 7 cm.
3 triangles attached to three sides of the square. A line bisecting one triangle is measured at 4 cm.
Area of a square = s² = (7cm)² = 49 cm²
Area of a triangle = hb/2 = (4cm*7cm)/2 = 14 cm²
Area of the 3 triangles = 14 cm² x 3 = 42 cm²
Total area of the logo = 49 cm² + 42 cm² = 91 cm²
The answer is A. I hope I helped
Answer:
csc
A
, as desired!
Step-by-step explanation:
cos
2
A
sin
A
+
sin
2
A
cos
A
,
=
cos
2
A
cos
A
+
sin
2
A
sin
A
sin
A
cos
A
,
=
cos
(
2
A
−
A
)
sin
A
cos
A
,
=
cos
A
sin
A
cos
A
,
=
1
sin
A
,
=
csc
A
, as desired!
I'm pretty sure it would be <span>x - y + 1 = 0 because if you plug in one of the coordinates into each equation, this is the only one that works.
</span><span>y - x + 1 = 0
2 - 1 + 1 = 0
2 = 0 not correct
</span><span>x - y + 1 = 0
1 - 2 + 1 = 0
0 = 0 correct
</span><span>-x - y + 1 = 0
-1 - 2 + 1 = 0
-2 = 0 not correct
</span>
Answer:
each notebook costs $2.70
each pack of pencils costs $1.50
Step-by-step explanation:
system of equations:
let p = pack of pencils
let n = notebook
3p + 5n = 18
4p + 4n = 16.8
I used the elimination method by multiplying the first equation by 4 and the second equation by -3
4(3p + 5n = 18) = 12p + 20n = 72
-3(4p + 4n = 16.8) = -12p -12n = -50.4
adding the new equations together you get: 8n = 21.6
n = 21.6/8
n = $2.70
solve for 'p':
3p + 5(2.7) = 18
3p + 13.5 = 18
3p = 4.5
p = $1.50
