Question

PLEASE HELP!! WILL GET BRAINIEST!!

Answer 1

1. C
2. C
3. C
4. A
5. B
Hope this helps!

Answer 2

Answer:

1.) Let's find out the slope. Checking the Graph, locating two coordinate points. Looking at the graph picking (-4,0) and (0,1)

Inserting those points into that slope formula:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ m=\frac{1-0}{0-(-4)} \\ m=\frac{1}{4}$

2) According to the second picture. Let's pick two other points. (1,0) and (1,1)

Inserting those points into the formula:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ m=\frac{1-0}{1-1)} \\ m=\frac{1}{0}$

a)0. False.

Thus it can't be 0, since it's not a constant function, and its line it's not parallel to axis x.

b) 1. False 1≠ 1/0

c) True. This quotient is not defined for the set of Real Numbers.

d) False.

3) In a perpendicular line its slope is given by -$\frac{-1}{m}$ of another line.

In addition to this we need to know the line general equation

$(y-y_{0})=m(x-x_{0})$ .

From this equation y - 2 = 7/3(x + 5) let's get the slope of our perpendicular line: m= -3/7x

The point (-4, 9) will supply the other two points, let's insert them all

y -9=-3/7(x+4)

C)

4)

a) True.  Easily checked by looking at the graph interception.

b) False.

c) False

d) False

5)

B) True. Since the y- intercept of y=|x| is 3.