9514 1404 393
Answer:
x = 10; WX = 5; HJ = 10
Step-by-step explanation:
The hash marks indicate that points W and X are midpoints of their respective segments. That makes WX a midline of the triangle. The midline is always half the length of the base (HJ). We can use this fact to write an equation relating the lengths.
HJ = 2·WX
x = 2(x -5) . . . .substitute the given expressions
x = 2x -10 . . . . eliminate parentheses
10 = x . . . . . . . add 10-x to both sides
This value of x tells you that ...
HJ = x = 10
WX = x -5 = 5
Answer :

Step-by-step explanation:
Its given that n is the middle out of the three consecutive integers . So ,
<u>The </u><u>last</u><u> </u><u>integer</u><u> </u><u>will</u><u> </u><u>be</u><u> </u><u>:</u><u>-</u><u> </u>
<u>The </u><u>next</u><u> </u><u>Integer</u><u> </u><u>will</u><u> be</u><u> </u><u>:</u><u>-</u>
Now the Question says that the three integers are multipled to give a product . So that would be.

Now thirdly it's given that n is added to the given integer . That would be ,
Here - n and +n gets cancelled. So we are ultimately left out with n³.
Hence the final number is a cube of some number.
Based on point P(0,16), we substitute in the parabola to find a.
16=a(0-3)^2-2 => a=(16+2)/9=2
so the parabola is
y=2(x-3)^2-2 ..........................(1)
Solve for zeroes of (1);
0=2(x-3)^2-2 => (x-3)^2=1 => x=2 or x=4
Now the line passes through (0,16), (4,0) => y,x intercepts are 16 & 4.
Using the symmetric form
x/4+y/16=1
4x+y=16 => y=16-4x
hello answer is ## because u need to find the alphabet sequence
Answer:
<h2>
![{g}^{ - 1} (x) = \sqrt[5]{ - x - 3}](https://tex.z-dn.net/?f=%20%7Bg%7D%5E%7B%20-%201%7D%20%28x%29%20%3D%20%20%5Csqrt%5B5%5D%7B%20-%20x%20-%203%7D%20)
</h2>
Step-by-step explanation:
<h3>

</h3>
To find the inverse of g(x) equate g(x) to y
That's
<h3>

</h3>
<u>Next interchange the terms</u>
x becomes y and y becomes x
We have
<h3>

</h3>
<u>Next make y the subject</u>
Multiply both sides by - 1
That's
<h3>

</h3>
Send 3 to the right side of the equation
That's

<u>Find the 5th root of both sides</u>
That's
<h3>
![\sqrt[5]{ {y}^{5} } = \sqrt[5]{ - x - 3} \\ y = \sqrt[5]{ - x - 3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B%20%7By%7D%5E%7B5%7D%20%7D%20%20%3D%20%20%5Csqrt%5B5%5D%7B%20-%20x%20-%203%7D%20%20%5C%5C%20y%20%3D%20%20%20%5Csqrt%5B5%5D%7B%20-%20x%20-%203%7D%20)
</h3>
We have the final answer as
<h3>
![{g}^{ - 1} (x) = \sqrt[5]{ - x - 3}](https://tex.z-dn.net/?f=%20%7Bg%7D%5E%7B%20-%201%7D%20%28x%29%20%3D%20%20%5Csqrt%5B5%5D%7B%20-%20x%20-%203%7D%20)
</h3>
Hope this helps you