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dsp73
3 years ago
8

Complete the equation of the line whose y-intercept is (0,6) and slope is 3

Mathematics
1 answer:
mihalych1998 [28]3 years ago
6 0
Equation is y=mx+b
where m= slope and b= y-intercept
so,
m= 3 and b= 6

answer: y= 3x + 6
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Someone please help me I don’t know this :(
Shalnov [3]

9514 1404 393

Answer:

  x = 10; WX = 5; HJ = 10

Step-by-step explanation:

The hash marks indicate that points W and X are midpoints of their respective segments. That makes WX a midline of the triangle. The midline is always half the length of the base (HJ). We can use this fact to write an equation relating the lengths.

  HJ = 2·WX

  x = 2(x -5) . . . .substitute the given expressions

  x = 2x -10 . . . . eliminate parentheses

  10 = x . . . . . . . add 10-x to both sides

This value of x tells you that ...

  HJ = x = 10

  WX = x -5 = 5

4 0
3 years ago
N is the middle integer of three consecutive positive integers.
abruzzese [7]

Answer :

\boxed{\textsf{ The final answer is \textbf{n}$^{\textbf{3}}$ .}}

Step-by-step explanation:

Its given that n is the middle out of the three consecutive integers . So ,

<u>The </u><u>last</u><u> </u><u>integer</u><u> </u><u>will</u><u> </u><u>be</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies Last \ Integer \ = \ n - 1

<u>The </u><u>next</u><u> </u><u>Integer</u><u> </u><u>will</u><u> be</u><u> </u><u>:</u><u>-</u>

\sf\implies Next \ Integer \ = \ n + 1

Now the Question says that the three integers are multipled to give a product . So that would be.

\sf\implies Product_{(three\ consecutive\ integers)}= (n-1)n(n+1) = (n^2-1)(n) = \pink{n^3-n}

Now thirdly it's given that n is added to the given integer . That would be ,

\sf\implies Adding\ n = \ n^3 - n + n = \pink{n^3}

Here - n and +n gets cancelled. So we are ultimately left out with n³.

Hence the final number is a cube of some number.

6 0
3 years ago
How do you do this problem?
erastova [34]

Based on point P(0,16), we substitute in the parabola to find a.

16=a(0-3)^2-2 => a=(16+2)/9=2

so the parabola is

y=2(x-3)^2-2 ..........................(1)

Solve for zeroes of (1);

0=2(x-3)^2-2 => (x-3)^2=1 => x=2 or x=4

Now the line passes through (0,16), (4,0) => y,x intercepts are 16 & 4.

Using the symmetric form

x/4+y/16=1

4x+y=16 => y=16-4x

8 0
3 years ago
What are the next letters BE GJ LO QT
kykrilka [37]

hello answer is ## because u need to find the alphabet sequence
6 0
3 years ago
Read 2 more answers
Inverse of g(x)=-x^5-3
Artyom0805 [142]

Answer:

<h2>{g}^{ - 1} (x) =  \sqrt[5]{ - x - 3}</h2>

Step-by-step explanation:

<h3>g(x) =  -  {x}^{5}  - 3</h3>

To find the inverse of g(x) equate g(x) to y

That's

<h3>y =  -  {x}^{5}  - 3</h3>

<u>Next interchange the terms</u>

x becomes y and y becomes x

We have

<h3>x =  -  {y}^{5}  - 3</h3>

<u>Next make y the subject</u>

Multiply both sides by - 1

That's

<h3>{y}^{5}  + 3 =  - x</h3>

Send 3 to the right side of the equation

That's

{y}^{5}  =  - x - 3

<u>Find the 5th root of both sides</u>

That's

<h3>\sqrt[5]{ {y}^{5} }  =  \sqrt[5]{ - x - 3}  \\ y =   \sqrt[5]{ - x - 3}</h3>

We have the final answer as

<h3>{g}^{ - 1} (x) =  \sqrt[5]{ - x - 3}</h3>

Hope this helps you

5 0
3 years ago
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