Question

Janet, an experienced shipping clerk, can fill a certain order in 10 hours. Bill, a new clerk, needs 11 hours to do the same

Answer 1

Answer:

$\boxed{\text{5.238 h}}$

Step-by-step explanation:

Janet's rate is 1/10 order/h; Bill's rate is 1/11 orders/h.

Let t = the number of hours

The condition is:

Work done by Jane + work done by Bill = 1 order

$\begin{array}{rcl}\dfrac{t}{10} + \dfrac{t}{11} & = & 1\\\\\dfrac{11t+10t}{110}& = & 1\\\\21t & = & 110\\t & = & \textbf{5.238 h}\\\end{array}\\\text{Working together, they will fill the order in \boxed{\textbf{5.238 h}} }$

Check:

$\begin{array}{rcl}\dfrac{5.238}{10} + \dfrac{5.238}{11} & = & 1\\\\0.5238 + 0.4762 & = & 1\\1.0000 & = &1\\\end{array}$