Answer:
P(2)=0 then x-2 is a factor of P(x)
Step-by-step explanation:
To see if (x-2) is a factor just plug in 2 for x into the polynomial expression.
2(2)^3-3(2)^2-17(2)+30
2(8)-3(4)-34+30
16-12-34+30
4-34+30
-30+30
0
Since P(2)=0 then x-2 is a factor
Answer:
11.1m/s to the right
Step-by-step explanation:
Momentum before = momentum after
m₁u₁+m₂u₂=(m₁+m₂)v
1000(20)+800(0)=(1000+800)v
20000 = 1800 v
v= 11.1m/s to the right (to the right because the number is positive)
If we multiply the first numbers in the three parentheses we get 9*12*2 = 216
then x's come to x to 1 and the y terms come to y^9
so the answer is 216y^9
The remainder is 49.
Hope it helps.
Ask me if u want solution too.
The function is:
f ( x ) = 1,000 · 2^x
x is the number of weeks.
1. y - intercept is : y = 1,000.
2. The y-intercept represents the cicada population at the start ( for x = 0 ).
f ( 0 ) = 1,000 · 2^0 = 1,000 · 1 = 1,000.
3. The 2 in the function shows that cicada population doubles every week.
