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garik1379 [7]
3 years ago
9

What is ten times less than 700?

Mathematics
2 answers:
baherus [9]3 years ago
7 0

600 subtract 700 with 10 douhhhhh, I had that question before and the answer was 600

Ghella [55]3 years ago
6 0
700/10 equals 70, so the answer is 70.
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How do I solve this? i missed ONE class
lisov135 [29]

Answer:

a < 42

Step-by-step explanation:

Question : 4a + 9a - 6a < 42

Answer :

4a + 9a - 6a < 42

Combine like terms.

13a - 6a < 42

7a < 42

Divide both sides by 7.

a < 42

Hope this helps you :-)

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6 0
2 years ago
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I need help real quick please!
iogann1982 [59]

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3 years ago
How many pairs of parallel line segments are shown? <br><br> 1. 8<br> 2. 24<br> 3. 4<br> 4. 18
kolezko [41]
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4 0
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Write an equation for the line that is parallel to the given line and that passes through the given point. y = –6x + 2; (–1, 2)
kap26 [50]
Parallel=same slope
Y=mx+b
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6 0
3 years ago
A website manager has noticed that during the evening​ hours, about 5 people per minute check out from their shopping cart and m
Over [174]

Answer:

a) Poisson distribution

b) 99.33% probability that in any one minute at least one purchase is​ made

c) 0.05% probability that seven people make a purchase in the next four ​minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

5 people per minute check out from their shopping cart and make an online purchase.

This means that \mu = 5

a) What model might you suggest to model the number of purchases per​ minute? ​

The only information that we have is the mean number of an event(purchases) in a time interval. Each event is also independent fro each other. So you should suggest the Poisson distribution to model the number of purchases per​ minute.

b) What is the probability that in any one minute at least one purchase is​ made? ​

Either no purchases are made, or at least one is. The sum of the probabilities of these events is 1. So

P(X = 0) + P(X \geq 1) = 1

We want to find P(X \geq 1)

So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-5}*(5)^{0}}{(0)!} = 0.0067

1 - 0.0067 = 0.9933.

99.33% probability that in any one minute at least one purchase is​ made

c) What is the probability that seven people make a purchase in the next four ​minutes?

The mean is 5 purchases in a minute. So, for 4 minutes

\mu = 4*5 = 20

We have to find P(X = 7).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-20}*(20)^{7}}{(7)!} = 0.0005

0.05% probability that seven people make a purchase in the next four ​minutes

8 0
3 years ago
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