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Andrew [12]
3 years ago
9

Twice the sum of x and y decreased by 21

Mathematics
1 answer:
Semenov [28]3 years ago
8 0
Answer: 2((x+y)-21)

Calculation/Explanation:

Twice the sum of x and y decreased by 21 means that you must add x and y first before decreasing by 21. The last step is to double the whole equation that we just performed.
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Step-by-step explanation:

you divide

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Insert geometric means in each geometric sequence.
Digiron [165]

Answer:

\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}

\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}

81, \underline{27, 9, 3, 1},\dfrac{1}{3}

Step-by-step explanation:

Given the Geometric sequences:

1. ___, 24, ___, ___, 3/64

2. ___, 1/4, 1/2, ___

3. 81, ___, ___, ___, ___, 1/3

To find:

The values in the blanks of the given geometric sequences.

Solution:

First of all, let us learn about the n^{th} term of a geometric sequence.

a_n=ar^{n-1}

Where a is the first term and

r is the common ratio by which each term varies from the previous term.

Considering the first sequence, we are given the second and fifth terms of the sequences.

Applying the above formula:

ar = 24\\ar^4 = \dfrac{3}{64}

Solving the above equation:

r = \dfrac{1}{8}

Therefore, the sequence is:

\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}

Considering the second given sequence:

ar = \dfrac{1}{4}\\ar^2 = \dfrac{1}{2}\\\text{Solving the above equations}, r = 2

Therefore, the sequence is:

\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}

Considering the third sequence:

a = 81\\ar^5=\dfrac{1}{3}\\\Rightarrow r = 3

Therefore, the sequence is:

81, \underline{27, 9, 3, 1},\dfrac{1}{3}

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Sqrt(50) = sqrt(25*2) = sqrt(25) * sqrt(2) = 5*sqrt 2, answer is A
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A trapezoid has two sets of parallel sides.<br><br> always<br> sometimes<br> never
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There is some disagreement whether parallelograms, which have two pairs of parallel sides, should be regarded as trapezoids. Some define a trapezoid as a quadrilateral having only one pair of parallel sides (the exclusive definition), thereby excluding parallelograms.

In other words, sometimes.
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