The Math Club is sponsoring a bake sale. If their goal is to raise at least $300, how many pies must they sell at $6.00 each in
order to meet that goal? Write, solve, and graph an inequality that represents this situation.
2 answers:
Given:
bake sale at least $300
price of each pie is $6.00
let the number of pies be represented by x.
Write the inequality:
6x <u>></u> 300
Solve the inequality:
6x <u>></u> 300
<u>÷6 ÷6</u>
x <u>></u> 50
Graph the inequality.
y = 6x
x is the number of pies sold; x at least 50 and gradually increases.
y is the total sales
Inequality: 6x <span>≤ 300 solution: x </span><span>≤ 50 (at least 50 pies must be sold) </span>
x = number of pies
6x <span>≤ 300
/6 /6
x </span>≤ 50 <span>
</span>
You might be interested in
312/17
= (306+6)/ 17
= 306/17+ 6/17
= 18+ 6/17
= 18 6/17
The final answer is 18 6/17~
<em>Answer:</em>
<em>1. 65 coins</em>
<em>2. 79 - (23 + 22 + 20) = n</em>
<em>Step-by-step explanation:</em>
<em>You can use the expression 23 + 22 + 20 to get the amount of coins that are not nickles. And for two? Try it yourself.</em>
<em>Hope this helps. Have a nice day.</em>
Answer:
5,500
Step-by-step explanation:
this is quite simple
multiply his earnings by a tenth
55,000 times 1/10
5,500
Answer:
I can´t see...
Step-by-step explanation:
You would start with the equation:Let m=number of miles
49.98+0.12m=35.98+0.17m
Then solve for m
You would then get
49.98+0.12m=35.98+0.17m
-0.12m -0.12m
49.98=35.98+0.05m
-35.98 -35.98
14 = 0.05m
---- --------
0.05 0.05
280=m
