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IRINA_888 [86]
3 years ago
14

The Math Club is sponsoring a bake sale. If their goal is to raise at least $300, how many pies must they sell at $6.00 each in

order to meet that goal? Write, solve, and graph an inequality that represents this situation.
Mathematics
2 answers:
soldi70 [24.7K]3 years ago
4 0
Given:
bake sale at least $300
price of each pie is $6.00
let the number of pies be represented by x.

Write the inequality:
6x <u>></u> 300  

Solve the inequality:
6x <u>></u> 300
<u>÷6       ÷6</u>
  x <u>></u> 50

Graph the inequality.
y = 6x

x is the number of pies sold; x at least 50 and gradually increases.
y is the total sales


butalik [34]3 years ago
4 0
Inequality: 6x <span>≤ 300      solution: x </span><span>≤ 50 (at least 50 pies must be sold) </span>

x = number of pies
6x <span>≤ 300 
/6       /6
x   </span>≤ 50 <span>

</span>
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In Ryan Corporation, the first shift produced 5 1/2 times as many light bulbs as the second shift. If the total light bulbs prod
tekilochka [14]

Answer:

Step-by-step explanation:

It appears that the number of bulbs produced on the first shift is quite a bit more than the second shift.  5.5 times more, actually.  That means that the first shift's output is based on the second shift's output.  Second shift produced an unknown number of bulbs, so we will call that number x.  First shift produced 5.5 times more, so first shift produced 5.5x.  The total number of bulbs produced between the 2 shifts is given as 16,250, so

x + 5.5x = 16,250 so

6.5x = 16,250 and

x = 2500

The second shift produced 2500 bulbs, and the first shift produced 5.5(2500) = 13,750 bulbs.

7 0
3 years ago
Can I have some help finding the area to this? Can someone also explain how to figure this out?? PLEASE
nignag [31]
Let's separate the hexagon into 5 shapes; 2 triangles on each side, and a rectangle in the middle. Now let's find the area of each of the smaller shapes.

Top left triangle:
The equation to find the area of a triangle is
(base = b, height = h, a = area)
a = b · h · \frac{1}{2}
Now let's add in our values and solve.
a = 2 · 4 · \frac{1}{2}
a = 8 · \frac{1}{2}
a = 4

Now since there are 4 of these triangles, and they're all the same size,
4 · 4 = 16
All of the triangles put together = 16cm²

The middle rectangle:
The equation to find the area of a rectangle is simple:
(w = width, l = length, a = area)
a = w · l
Now let's put in our values and solve.
a = 4 · 8
a = 32

The rectangle is 32cm²

Now let's add the areas together. 
32 + 16 = 48

The answer is <span>48cm²

Hope this helped! If you have anymore questions or don't understand, please comment or DM me. :)
</span>
4 0
3 years ago
Which point is closest to 7 on the number line?<br> ET<br> C0
liraira [26]

Answer: ET

Step-by-step explanation:

7 0
3 years ago
Solve for r write the answer in simplified form<br><br> 7 = - 7r
alex41 [277]

Answer:

r = -1

Step-by-step explanation:

To get r isolated, you have to divide each side by -7

7 divided by -7 is -1, therefore r = -1

3 0
3 years ago
Suppose that θ is an acute angle of a right triangle and that sec(θ)=52. Find cos(θ) and csc(θ).
insens350 [35]

Answer:

\cos{\theta} = \dfrac{1}{52}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

Step-by-step explanation:

To solve this question we're going to use trigonometric identities and good ol' Pythagoras theorem.

a) Firstly, sec(θ)=52. we're gonna convert this to cos(θ) using:

\sec{\theta} = \dfrac{1}{\cos{\theta}}

we can substitute the value of sec(θ) in this equation:

52 = \dfrac{1}{\cos{\theta}}

and solve for for cos(θ)

\cos{\theta} = \dfrac{1}{52}

side note: just to confirm we can find the value of θ and verify that is indeed an acute angle by \theta = \arccos{\left(\dfrac{1}{52}\right)} = 88.8^\circ

b) since right triangle is mentioned in the question. We can use:

\cos{\theta} = \dfrac{\text{adj}}{\text{hyp}}

we know the value of cos(θ)=1\52. and by comparing the two. we can say that:

  • length of the adjacent side = 1
  • length of the hypotenuse = 52

we can find the third side using the Pythagoras theorem.

(\text{hyp})^2=(\text{adj})^2+(\text{opp})^2

(52)^2=(1)^2+(\text{opp})^2

\text{opp}=\sqrt{(52)^2-1}

\text{opp}=\sqrt{2703}

  • length of the opposite side = √(2703) ≈ 51.9904

we can find the sin(θ) using this side:

\sin{\theta} = \dfrac{\text{opp}}{\text{hyp}}

\sin{\theta} = \dfrac{\sqrt{2703}}{52}}

and since \csc{\theta} = \dfrac{1}{\sin{\theta}}

\csc{\theta} = \dfrac{52}{\sqrt{2703}}

4 0
3 years ago
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