Answer:
Step-by-step explanation:
If the diagonals of the rectangle are congruent,
AC = BD
By using formula to calculate the distance between two points,
Distance between two points = 
Distance between A(0, -3) and C(2, 8),
AC = 
= 
= 
Similarly, distance between two points B(-4, 0) and D(6, 5),
BD = 
= 
= 
Therefore, both the diagonals are congruent.
Hence, given quadrilateral ABCD is a rectangle.
The area of a rhombus is half of the product of the lengths of the diagonals.
area = (7.5 yd + 7.5 yd)(13 yd + 13 yd)/2
area = (15 yd)(26 yd)/2
area = 390 yd^2/2
area = 195 yd^2
Answer: 195
I don't recognize this problem, please make sure the input is complete.
Answer:
9/4
Step-by-step explanation:
5×|-2-7(3)|-2×17
5×|-2-21|-34
5×|-23|-34
5×23-34
115-34=81
22+sq rt(7×28) 28=4×7 sq rt= 2×2×7×7
22+2×7=22+14=36
81÷9/36÷9=9/4