Refer to the diagram shown below.
Because ΔABC is isosceles and AB = AC, therefore
m∠C = m∠B = (3x + 5)°
The sum of angles in a triangle is 180°, therefore
2(3x + 5) + 2x - 20 = 180
6x + 10 + 2x - 20 = 180
8x - 10 = 180
8x = 190
x = 23.75°
Therefore
m∠C = 3x + 5 = 3(23.75) + 5 = 76.25°
Answer: 76.25°
48 and 78(try to see if its 6)
The answer is the angles are neither complementary nor supplementary, because complementary is to add up to 90° and supplementary is to add up to 180°, and these angles add up to 169°. I hope this helps!
1 - 3x = x + 3 |subtract 1 from both sides
-3x = x + 2 |subtract x from both sides
-4x = 2 |divide both sides by (-4)
x = 2/-4
x = -0.5